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drek231 [11]
1 year ago
6

Ebony is cutting dough for pastries in her bakery. She needs all the pieces to be congruent triangles and has ensured that segme

nt EF ≅ segment ON and ∠MON is congruent to ∠GEF. What would Ebony need to compare in order to make sure the triangles are congruent by AAS?

Mathematics
1 answer:
Vaselesa [24]1 year ago
5 0

The congruent statements given are:

\begin{gathered} \overline{EF}\cong\overline{ON} \\ \angle MON\cong\angle GEF \end{gathered}

It is required to state what statement will be needed to make sure the triangles are congruent by AAS.

Recall the Angle-Angle-Side (AAS) Theorem:

From the theorem, it follows that a non-included pair of sides will be required.

Hence, the required pair of sides to be compared are:

\overline{NM}\text{ and }\overline{FG}

The third choice is the correct option.

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If someone could help it would be greatly appreciated.
Alisiya [41]

Answer:

a) line segment

b) point

c) line

Step-by-step explanation:

A line segment is made up of 2 points.

No matter where the lines intersect (doesn't have to be perpendicular), it forms a point.

A line is straight, hence the 3 collinear points.

3 0
3 years ago
Direct mail advertisers send solicitations​ ("junk mail") to thousands of potential customers in the hope that some will buy the
harina [27]

Answer:

The interval is (.0817, .118).

Step-by-step explanation:

Let's make this interval! The easy way is to go to STAT->TEST->A, 1-prop z-int, but I will show the long way.

<u>1. Conditions</u>

First we must check the conditions.

<em>Randomization condition: </em>The sample is given to be random, so we can assume independence.

<em>Success/failure condition: </em>Both np>10 and nq>10 must be met.

  • np = 1030(103/1030) = 103 ✓
  • nq = 1030(927/1030) = 927 ✓

<em>10% condition: </em>The sample cannot be greater than 10% of the population.

  • 10n < N, 10(1030) < 200000 ✓

All conditions are met, so we can use <u>a 1-proportion z-interval</u> to represent the data.

<u></u>

<u>2. Mechanics</u>

<u>Find </u>\hat{p}<u>, the sample proportion.</u>

103/1030 = .1

\hat{q}, then, the probability of not p, is 1 - .1 = .9

<u>Find z* (z star), the critical z-value.</u>

You can do this on your calculator using 2nd->VARS->3 (or you can memorize it - it's 1.96. Winky face.) This is called the invNorm function, that takes the left side area under the normal curve. But what do we plug in to the invNorm function?

invNorm(.975) = 1.96

<u>Plug values into the equation.</u>

\hat{p} ± z*\sqrt{\frac{\hat{p}\hat{q}}{n} }

.1 ± 1.96\sqrt{\frac{.1*.9}{1030} }

.1 ± 1.96(.00935)

.1 - .0183 = .0817

.1 + .0183 = .118

(.0817, .118)

<u>3. Conclusion</u>

Based on this sample, we are 95% confident that the proportion of people the company contacts who may buy something is between .0817 and .118. That isn't very likely, but maybe they'll make a little profit!

5 0
3 years ago
The diagonals of a rhombus are 21 m and 32 m. What is the area of the rhombus?<br> 30 POINTS
Wittaler [7]
I have included attachment below

so since a rhombus is 2 pairs of paralell sides, we can cut it into 4 triangles
we can see that we can take the bottom 2 triangles and put them on top to get a rectangle that is width 21 and height 32/2 (16=height
area of rectangle=legnth times width=16 times 21=336 m^2

answer is 336 m^2

5 0
2 years ago
A Florida factory produces fishing reels at a rate of 800 per day, every day. In April, they
Serjik [45]
The factory normally produces 800 reels a day.
They have to cut their production by 1/5, however.
800 * 4/5 = 640 reels a day.

30 days would mean 640 * 30 reels...19200 reels.

This is less than 20,000, so the factory will NOT be able to produce enough reels.
8 0
3 years ago
Read 2 more answers
When your dividing zero by any numbers is the answer always zero
djyliett [7]
Yes. The answer to any number divided by zero will be zero.
5 0
3 years ago
Read 2 more answers
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