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Stells [14]
3 years ago
9

Please help , maths watch pythagoras

Mathematics
1 answer:
TiliK225 [7]3 years ago
6 0
Square Root of 5^2 + 3^2

Square root of 25 + 9

Square root of 34 = 5.83095....

= 5.83 (3 s.f)

Hope this has helped you
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Select the expression that is equivalent to the expression given.
STALIN [3.7K]
You do what is asked for in the parentheses then multiply by the number outside of them.

6 0
3 years ago
What is the domain of the function? y=3√x-1
geniusboy [140]
X - 1 is inside a cubic root.
The cubic root of a positive number is positive.
The cubic root of zero is zero.
The cubic root of a negative number is negative.
That means that the cubic root of any real number is also a real number.
The domain is all real numbers.
Answer: Choice A.
3 0
3 years ago
You invest $1,050.00, buying stock in a company at $10.00/share. The shares increase in value by 13% the first year and decrease
allochka39001 [22]
Number of shares
1050/10=105
After one year share value
10×(1+0.13)=11.3
After the second year share value
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Total
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3 0
2 years ago
Read 2 more answers
Write an equation in which the quadratic expression 3x^2+6x-24 equals 0. Show the expression in factored form and explain what y
mr_godi [17]

Answer:

3x² + 6x - 24 = 0

(3x - 6)(x + 4) = 0

x = -4 , x = 2 when y = 0

Step-by-step explanation:

3x² + 6x - 24 = 0

(3x - 6)(x + 4) = 0

Means

3x - 6 = 0 ⇒ 3x = 6 ⇒ x = 6 ÷ 3 = 2

x + 4 = 0 ⇒ x = -4

The Parabola which represents the quadratic equation intersects x-axis at

points (2 , 0) and (-4 , 0)

5 0
3 years ago
The masses mi are located at the points Pi. Find the moments Mx and My and the center of mass of the system. m1 = 4, m2 = 3, m3
viva [34]

Answer:

M_x= 8

M_y = 6

Therefore the co-ordinate of the center of mass is = (\frac{4}{5},\frac{3}{5})

Step-by-step explanation:

Center of mass: Center of mass of an object is a point on the object. Center of mass is the average position of the system.

Center of mass of a triangle is the centriod of a triangle.

Given that m₁= 4, m₂=3, m₃=3 and the points are P₁(2,-3), P₂(-3,1) and P₃(3,5)

M_x = ∑(mass × x-co-ordinate)

M_y = ∑(mass × y-co-ordinate)

Therefore  

M_x = (4×2)+{3×(-3)}+(3×3)

     =8

M_y = {4×(-3)}+{3×1}+(3×5)

    =6

The x co-ordinate of the center of mass is the ratio of M_x to the total mass.

The y co-ordinate of the center of mass is the ratio of M_y to the total mass.

Total mass (m) = m₁+ m₂+ m₃

                        = 4+3+3

                        =10

The x co-ordinate of the center of mass is \frac {8}{10} = \frac {4}{5}

The y co-ordinate of the center of mass is \frac{6}{10}=\frac{3}{5}

Therefore the co-ordinate of the center of mass is = (\frac{4}{5},\frac{3}{5})

4 0
3 years ago
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