Information goes into a computer through _______ and comes our through ______

The average pH of citrus fruits is 2.2, and this value has been stored in the variable avg_citrus_pH . Provide a statement to di

olasank [31]

Answer:

The statement in Python is:

print("The average pH of citrus fruits is ",avg_citrus_pH)

Java

System.out.print("The average pH of citrus fruits is "+avg_citrus_pH);

C++

cout<<"The average pH of citrus fruits is "<<avg_citrus_pH;

Explanation:

The programming language is not stated; so, I answered the question in 3 languages (Python, Java and C++)

Assume that avg_citrus_pH has been declared and initialized; all you need to do is invoke a print statement and then append the variable

In Python, use print()

In c++, use cout<<

In Java, use System.out.print()

So, the statements are:

Python:

print("The average pH of citrus fruits is ",avg_citrus_pH)

Java

System.out.print("The average pH of citrus fruits is "+avg_citrus_pH);

C++

cout<<"The average pH of citrus fruits is "<<avg_citrus_pH;

8 0

2 years ago

If a 60 lb. load is placed on the platform, what will the pressure gauge reading be if the piston area is 5 sq.in? Give your ans

Doss [256]

Answer:

The pressure gauge reading will be;

12 psi

Explanation:

The question relates to relationship of pressure and area

The given parameters for the measurement are;

The weight of the load = 60 lb

The required area of the piston = 5 in.²

Pressure exerted by a force can be defined as follows;

$Pressure = \dfrac{Force}{Area}$

The weight of the load = The force applied by the load

Therefore;

$Pressure = \dfrac{Force}{Area} = \dfrac{60 \ lb}{5 \ in.^2} = 12\dfrac{lb}{in.^2} = 12 \ psi$

The gauge reading will be 12 psi.

7 0

3 years ago

Read 2 more answers

In the original UNIX operating system, a process executing in kernel mode may not be preempted. Explain why this makes (unmodifi

Elena L [17]

Answer:

the preemption is -> The ability of the operating

system to preempt or stop a currently

scheduled task in favour of a higher priority

task. The scheduling may be one of, but not

limited to, process or 1/0 scheduling etc.

Under Linux, user-space programs have always

been preemptible: the kernel interrupts user

space programs to switch to other threads,

using the regular clock tick. So, the kernel

doesn't wait for user-space programs to

explicitly release the processor (which is the

case in cooperative multitasking). This means

that an infinite loop in an user-space program

cannot block the system.

However, until 2.6 kernels, the kernel itself was

not preemtible: as soon as one thread has

entered the kernel, it could not be preempted to

execute an other thread. However, this absence

of preemption in the kernel caused several

oroblems with regard to latency and scalability.

So, kernel preemption has been introduced in

2.6 kernels, and one can enable or disable it

using the cONFIG_PREEMPT option. If

CONFIG PREEMPT is enabled, then kernel code

can be preempted everywhere, except when the

code has disabled local interrupts. An infinite

loop in the code can no longer block the entire

system. If CONFIG PREEMPT is disabled, then

the 2.4 behaviour is restored.

So it suitable for real time application. Only

difference is we don't see many coders using it

5 0

3 years ago

a cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits such that the giv

Leokris [45]

Using the knowledge in computational language in C++ it is possible to write a code that cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits

<h3>Writting the code:</h3>

#include <bits/stdc++.h>

using namespace std;

// chracter to digit mapping, and the inverse

// (if you want better performance: use array instead of unordered_map)

unordered_map<char, int> c2i;

unordered_map<int, char> i2c;

int ans = 0;

// limit: length of result

int limit = 0;

// digit: index of digit in a word, widx: index of a word in word list, sum: summation of all word[digit]

bool helper(vector<string>& words, string& result, int digit, int widx, int sum) {

if (digit == limit) {

ans += (sum == 0);

return sum == 0;

}

// if summation at digit position complete, validate it with result[digit].

if (widx == words.size()) {

if (c2i.count(result[digit]) == 0 && i2c.count(sum%10) == 0) {

if (sum%10 == 0 && digit+1 == limit) // Avoid leading zero in result

return false;

c2i[result[digit]] = sum % 10;

i2c[sum%10] = result[digit];

bool tmp = helper(words, result, digit+1, 0, sum/10);

c2i.erase(result[digit]);

i2c.erase(sum%10);

ans += tmp;

return tmp;

} else if (c2i.count(result[digit]) && c2i[result[digit]] == sum % 10){

if (digit + 1 == limit && 0 == c2i[result[digit]]) {

return false;

}

return helper(words, result, digit+1, 0, sum/10);

} else {

return false;

}

// if word[widx] length less than digit, ignore and go to next word

if (digit >= words[widx].length()) {

return helper(words, result, digit, widx+1, sum);

}

// if word[widx][digit] already mapped to a value

if (c2i.count(words[widx][digit])) {

if (digit+1 == words[widx].length() && words[widx].length() > 1 && c2i[words[widx][digit]] == 0)

return false;

return helper(words, result, digit, widx+1, sum+c2i[words[widx][digit]]);

}

// if word[widx][digit] not mapped to a value yet

for (int i = 0; i < 10; i++) {

if (digit+1 == words[widx].length() && i == 0 && words[widx].length() > 1) continue;

if (i2c.count(i)) continue;

c2i[words[widx][digit]] = i;

i2c[i] = words[widx][digit];

bool tmp = helper(words, result, digit, widx+1, sum+i);

c2i.erase(words[widx][digit]);

i2c.erase(i);

}

return false;

}

void isSolvable(vector<string>& words, string result) {

limit = result.length();

for (auto &w: words)

if (w.length() > limit)

return;

for (auto&w:words)

reverse(w.begin(), w.end());

reverse(result.begin(), result.end());

int aa = helper(words, result, 0, 0, 0);

}

int main()

{

ans = 0;

vector<string> words={"GREEN" , "BLUE"} ;

string result = "BLACK";

isSolvable(words, result);

cout << ans << "\n";

return 0;

}

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3 0

1 year ago

Given a sorted array of integers created on the heap, its size and a new integer, design a function which will enlarge the array

Debora [2.8K]

Using the computational language in C++ to write a code that will organize the values in an array through a mathematical condition.

<h3>writing code in C++</h3>

#include <bits/stdc++.h>

using namespace std;

int getIndexInSortedArray(int arr[], int n, int idx)

{

/* Count of elements smaller than current

element plus the equal element occurring

before given index*/

int result = 0;

for (int i = 0; i < n; i++) {

if (arr[i] < arr[idx])

result++;

if (arr[i] == arr[idx] && i < idx)

result++;

}

return result;

}

int main()

{

int arr[] = { 3, 4, 3, 5, 2, 3, 4, 3, 1, 5 };

int n = sizeof(arr) / sizeof(arr[0]);

int idxOfEle = 5;

cout << getIndexInSortedArray(arr, n, idxOfEle);

return 0;

}

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7 0

2 years ago

Information goes into a computer through _______ and comes our through _______

Information goes into a computer through _ and comes our through _