Question

Given g (x)=-x^2+10x-3 Find g (-3)

Answer 1

Answer:

The value of g(x) at x=-3 is -42

That is g(-3)=-42

Step-by-step explanation:

Given that the function g is defined by $g(x)=-x^2+10x-3$

To find the value of g(-3) :

That is to find the value of g(x) at x=-3 :

$g(x)=-x^2+0x-3$

Put x=-3 in the above function we get

$g(-3)=-(-3)^2+10(-3)-3$

$=-(9)-30-3$

$=-9-33$

$=-42$

Therefore g(-3)=-42

The value of g(x) at x=-3 is -42

That is g(-3)=-42