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2 years ago

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A super train travels 1,500 miles in 12.5 hours. How many miles does it travel in one hour?

1 answer:

katen-ka-za [31]2 years ago

6 0

Let's treat the speed in one hour as a variable.
We can say that 1500=12.5x
Divide by 12.5
1500/12.5 = x
x = 120
120 mph is your answer.

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A consumer products company found that 44% of successful products also received favorable results from test market research, w

Korolek [52]

Answer:

0.80
0.289
0.20
0.711

Step-by-step explanation:

Given:

$P(S\cap F)=0.44\\P(S\cap F^{c})=0.13\\P(S^{c}\cap F^{c}) = 0.32\\P(S^{c}\cap F) = 0.11$

The rule of total probability states that:

$P(A) = P(A\cap B) + P(A\cap B^{c})$

Compute the individual probabilities as follows:

$P(S) = P(S\cap F) + P(S\cap F^{c})\\=0.44+0.13\\0.57$

$P(S^{c}) = 1 - P(S)\\=1-0.57\\=0.43$

$P(F) = P(S\cap F) + P(S^{c}\cap F)\\=0.44+0.11\\=0.55$

$P(F^{c})=1-P(F)\\=1-0.55\\=0.45$

Conditional probability of an event A given B is:

$P(A|B)=\frac{P(A\cap B)}{P(B)}$

Compute the value of $P(S|F)$ :

$P(S|F)=\frac{P(S\cap F)}{P(F)}\\=\frac{0.44}{0.55}\\=0.80$

Compute the value of $P(S|F^{c})$

$P(S|F^{c})=\frac{P(S\cap F^{c})}{P(F^{c})}\\=\frac{0.13}{0.45}\\=0.289$

Compute the value of $P(S^{c}|F)$

$P(S^{c}|F)=\frac{P(S^{c}\cap F)}{P(F}\\=\frac{0.11}{0.55}\\=0.20$

Compute the value of $P(S^{c}|F^{c})$

$P(S^{c}|F^{c})=\frac{P(S^{c}\cap F^{c})}{P(F^{c})}\\=\frac{0.32}{0.45}\\=0.711$

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3 years ago

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Murljashka [212]

The answer is 99.4 (99.4194 to be exact)

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andre [41]

30.8

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2 years ago

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Softa [21]

Answer:

There is no solution for given system of inequalities.

Step-by-step explanation:

The system of linear inequalities are given by

$y > \frac{3}{2} x - 1$ ...... (1) and

$y < \frac{3}{2} x - 1$ .......... (2)

The solution of the inequality $y > \frac{3}{2} x - 1$ is shown in the graph by the blue shaded zone and the solution of the inequality $y < \frac{3}{2} x - 1$ is shown in the graph by the red zone.

And it is clear that the solution of the system of inequality equation does not include the line $y = \frac{3}{2} x - 1$

Again, there is no overlap of the blue zone and the red zone so as to indicate solutions for both the inequalities.

Therefore, there is no solution for inequalities (1) and (2). (Answer)

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3 years ago