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Nikitich [7]
3 years ago
5

This hanger is in balance. There are two labeled weights of 5 grams and one of 33 grams. The four circles each have the same wei

ght. 33 5 5 What is the weight of each circle, in grams?
4/33
33
33/4
38/4​
Mathematics
1 answer:
kvv77 [185]3 years ago
3 0

Answer:

33

Step-by-step explanation:

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A sequence of numbers is formed by the iterative process Xn+1 = (Xn )2 – Xn
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Step-by-step explanation:

X1 = 1

X2 = (X1) 2 - X1

X2 = 2 - 1

X2 = 1. implies that the second term of the sequence is 1.

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42 divided by 6 in repeated subtraction
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42 - 6 = 36 - 1 36 - 6 = 30 - 2 30 - 6 = 24 - 3 24 - 6 = 18 - 4 18 - 6 = 12 - 5 12 - 6 = 6 - 6 6 - 6 = 0 - 7 42/6 = 7
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What is the the correct order for least to greatesed in these fractions,5/6,7/12 and 3/4
scZoUnD [109]

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7/12 3/4 5/6

Step-by-step explanation:

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3 years ago
Please solve this question!!​
GaryK [48]

Answer:  (i) 1/221     (ii) 11/221      (iii) 95/663        (iv) 1/663

<u>Step-by-step explanation:</u>

(i) A deck of cards contains 4 Kings out of 52 total cards

1st draw: 4 Kings out of 52 total cards → 4/52 = 1/13

2nd draw: 3 remaining Kings out of 51 total remaining cards  →  3/51 = 1/17

  <u>1st Draw </u>                   <u>2nd Draw </u>                  <u>Outcome</u>         <u>Probability</u>

 King: P(K) = 1/13        King: P(K₂/K₁) = 1/17     King, King       (1/13) x (1/17) = 1/221

*************************************************************************************************

(ii) A deck of cards contains 4 Jacks, 4 Queens, & 4 Kings out of 52 total cards

1st draw: 12 Face cards out of 52 total cards → 12/52 = 3/13

2nd draw: 11 remaining Face cards out of 51 total remaining cards  →  11/51

<u>1st Draw </u>                 <u>2nd Draw </u>                  <u>Outcome</u>       <u>Probability</u>

 Face: P(F) = 3/13    Face: P(F₂/F₁) = 11/51   Face,Face     (3/13) x (11/51) = 11/221

*************************************************************************************************

(iiI) A deck of cards contains 26 black cards out of 52 total cards but there are 2 black Jacks, 2 black Queens, and 2 black Kings.

1st draw: 20 Black (not Face) cards out of 52 total cards → 20/52 = 5/13

2nd draw: 19 remaining Black (not Face) cards out of 51 total remaining cards  →  19/51

  <u>1st Draw </u>                 <u>2nd Draw </u>                       <u>Outcome</u>   <u>Probability</u>

Black: P(B~) = 5/13   Black: P(B~₂/B~₁) = 19/51    B~,B~    (5/13) x (19/51) = 95/663

*************************************************************************************************

(ii) A deck of cards contains 4 Aces out of 52 total cards

1st draw: 4 Aces out of 52 total cards → 4/52 = 1/13

2nd draw: 1 Queen of Hearts out of 51 total remaining cards  →  1/51

  <u>1st Draw </u>                 <u>2nd Draw </u>                   <u>Outcome</u>         <u>Probability</u>

 Ace: P(A) = 1/13      Qh: P(Qh₂/A₁) = 1/51   Ace,Queen(h)   (1/13) x (1/51) = 1/663

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4 years ago
Which table has a constant of proportionality between y and x of 4
Agata [3.3K]
I think the answer to this is 4 I think
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