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irinina [24]
3 years ago
5

What's 5 - the square root of x + 10 = the square root of 7 - x

Mathematics
1 answer:
Tcecarenko [31]3 years ago
3 0
\bf 5-\sqrt{x+10}=\sqrt{7-x}\impliedby \textit{squaring both sides}
\\\\\\
(5-\sqrt{x+10})^2=(\sqrt{7-x})^2
\\\\\\
(5^2)-10\sqrt{x+10}+(x+10)=7-x
\\\\\\
35-10\sqrt{x+10}+x=7-x\implies 28-10\sqrt{x+10}+2x=0
\\\\\\
2x+28=10\sqrt{x+10}\implies x+14=5\sqrt{x+10}\impliedby 
\begin{array}{llll}
squaring\ both\\
sides\ again
\end{array}
\\\\\\


\bf (x^2)+28x+(14^2)=5^2(x+10)\implies x^2+28x+196=25x+250
\\\\\\
\begin{array}{lcclll}
x^2&+3x&-54&=0\\
&\uparrow &\uparrow \\
&-6+9&-6\cdot 9
\end{array} \implies (x+9)(x-6)=0\implies 
\begin{cases}
x+9=0\\
\boxed{x=-9}\\
-----\\
x-6=0\\
\boxed{x=6}
\end{cases}
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Step 1: Simplify both sides of the equation.

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16+−24x+8x=−25x+52

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8 0
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Step-by-step explanation:

Given:

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