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3 years ago

Write in exponential form: 5yxyxyxy

1 answer:

5 0

Exponential form has the little number exponent at the top but sadly I can only represent that here with a ^ meaning to the power of.

5y^4*x^3

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Write (2p)^4 without exponents.

Fed [463]

Answer:

= 8p

Step-by-step explanation:

Steps

2p · 4

Remove parentheses: (a) = a

= 2p · 4

Multiply the numbers: 2 · 4 = 8

= 8p

5 0

3 years ago

Se hizo un descuento por entrada así:10 % f1, 8 % f2, 6 % f3 y 4 % f4. Si los grupos entraron en las franjas 1, 2 y 4, ¿cuánto d

Sedaia [141]

Trying b and tell me is not correct
Please tell me

6 0

3 years ago

3980 divided by 26 (put remainders not decimals please!)

AlekseyPX

The answer is 156 r-2

5 0

3 years ago

Read 2 more answers

How do you rationalize the numerator in this problem?

maw [93]

To solve this problem, you have to know these two special factorizations:

$x^3-y^3=(x-y)(x^2+xy+y^2)\\ x^3+y^3=(x+y)(x^2-xy+y^2)$

Knowing these tells us that if we want to rationalize the numerator. we want to use the top equation to our advantage. Let:

$\sqrt[3]{x+h}=x\\ \sqrt[3]{x}=y$

That tells us that we have:

$\frac{x-y}{h}$

So, since we have one part of the special factorization, we need to multiply the top and the bottom by the other part, so:

$\frac{x-y}{h}*\frac{x^2+xy+y^2}{x^2+xy+y^2}=\frac{x^3-y^3}{h*(x^2+xy+y^2)}$

So, we have:

$\frac{x+h-h}{h(\sqrt[3]{(x+h)^2}+\sqrt[3]{(x+h)(x)}+\sqrt[3]{x^2})}=\\ \frac{x}{\sqrt[3]{(x+h)^2}+\sqrt[3]{(x+h)(x)}+\sqrt[3]{x^2}}$

That is our rational expression with a rationalized numerator.

Also, you could just mutiply by:

$\frac{1}{\sqrt[3]{x_h}-\sqrt[3]{x}} \text{ to get}\\ \frac{1}{h\sqrt[3]{x+h}-h\sqrt[3]{h}}$

Either way, our expression is rationalized.

7 0

3 years ago

Whats the difference between a $20,000 and a $50,000 annual salary over a lifetime?

laiz [17]

The difference between the two salaries is $30,000
50,000
-20,000
__________
30,000

7 0

3 years ago