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3 years ago

Can someone help me with factoring by grouping

Mathematics

2 answers:

Helga [31]3 years ago

8 0

Answer:

(x-2)(x+5)

Step-by-step explanation:

idk how to explain but..

First find two factors that make x^2 which is x and x: (x ?)(x ?)

Then because the last number is (-)10, you now know that there is a positive and negative symbol: (x + ?)(x-?)

Lastly, you have to find two factors of 10 that when subtracted equal to positive 3. A +5 and -2 when multiplied will equal to -10, and when subtracted will make +3. Then you can use the FOIL method to double check. im sorry.. ive never done this before lolol

when foiled: x^2 + 5x -2x - 10; x^2+3x-10

Wittaler [7]3 years ago

6 0

Factor : x^2+3x-10

Answer = (x - 2)(x + 5)

Explanation:

Y = x^2 + 3x - 10.

Find 2 numbers knowing sum (3) and product (-10).

Factor pairs of (-10) -> (-1, 10)(-2, 5). This sum is 3 = b. The 2 numbers are: -2 and 5.

y = (x - 2)(x + 5).

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Step-by-step explanation:

3 0

3 years ago

F(-2) if f (x) = -3x+7

katrin [286]

1 is the awnser to this problem

4 0

3 years ago

A boat traveled north for 28 miles, then turned x° southwest and traveled for 25 miles before stopping. When it stopped, the boa

zavuch27 [327]

Law of cosine is applicable to all the triangles. The value of the angle by which the boat turns is 39.195°.

<h3>What is the law of cosine?</h3>

Law of cosine helps us to find the third side of the triangle when 2 sides and an angle are known. It is formulated as,

$c=\sqrt{a^{2}+b^{2}-2 a b \cdot \cos \gamma}$

a, b, c is the sides of the triangle and,

$\gamma$ = angle opposite c

A.)

Given to us

A boat traveled north for 28 miles, then turned x° southwest and traveled for 25 miles before stopping.

When it stopped, the boat was 18 miles from its starting point.

According to the given statements, sides and angles can be written,

a = 25 miles

b = 28 miles

c = 18 miles

$\theta = x^o$

Substitute the values,

$c=\sqrt{a^{2}+b^{2}-2 a b \cdot \cos \gamma}$

$18=\sqrt{25^{2}+28^{2}-2(25)(28) \cdot \cos \theta}\\\\\theta = 39.195^o$

Hence, the value of the angle by which the boat turns is 39.195°.

B.)

Given to us

Starting at the dock, it travels 18 miles to the left, then 25 miles up and to the right, and then 28 miles down and back to the dock.

The angle between 25 miles and 28 miles is x degrees.

According to the given statements, sides and angles can be written,

a = 25 miles

b = 28 miles

c = 18 miles

$\theta = x^o$

Substitute the values,

$c=\sqrt{a^{2}+b^{2}-2 a b \cdot \cos \gamma}$

$18=\sqrt{25^{2}+28^{2}-2(25)(28) \cdot \cos \theta}\\\\\theta = 39.195^o$

Hence, the value of the angle by which the boat turns is 39.195°.

Learn more about the Law of cosine:

brainly.com/question/17289163

5 0

3 years ago

Can someone help me with this question?

Lemur [1.5K]

The third sentence !

8 0

3 years ago

0/1 Solve the equation by completing the square. Round your answer to the nearest hundredth, if necessary x^2+18x=7

11111nata11111 [884]

Answer:

The solution to the equation is x = 0.38 or -18.38

Step-by-step explanation:

x^2+18x=7 can be properly written as

$x^{2} +18x =7$

To solve by completing the square, divide the coefficient of x by 2, square and then add to both sides

i.e 18/2 = 9

Then add 9² to both sides of the equation

$x^{2} +18x + 9^{2} = 7 + 9^{2}$

This becomes

$(x+9)^{2} = 7 + 81$

$(x+9)^{2} = 88$

$x+9 = \pm \sqrt{88}$

$x = -9 \pm\sqrt{88}$

$x = -9 \pm 9.38$

∴ $x = -9+9.38 or -9-9.38$

$x = 0.38 or -18.38$

Hence, x = 0.38 or -18.38

7 0

3 years ago