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3 years ago

Find the measures of each angle in the triangle.

Mathematics

1 answer:

Rufina [12.5K]3 years ago

3 0

We use 2 different rules here:

1) sum of angles in a triangle is equal to 180 degrees

2) when a triangle side is a diameter of the circle, then angle opposite to diameter is equal to 90 degrees.

so from 2) we know that B= 90

then from first one:

sum of angles = 180 = 90 + (3x + 6) + x = 96 + 4x

so 180 - 96 = 4x
so x = 84/4
x = 21

so answer is
A= 3x+ 6 = 63 + 6 = 69
B = 90
C = 21

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Triangle SQT is isosceles. The measure of angle STQ is 48°. Triangle S Q T is cut by perpendicular bisector T R. The lengths of

igomit [66]

Answer:

$m\angle STR=24^o$

Step-by-step explanation:

we know that

$m\angle STQ=m\angle STR+m\angle RTQ$ ---> by addition angle postulate

we have

$m\angle STQ=48^o$ ----> given problem

$m\angle STR=m\angle RTQ$ ----> given problem

substitute in the expression above

$48^o=2m\angle STR$

Divide by 2 both sides

$m\angle STR=24^o$

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4 years ago

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Line segment BD is a diameter of circle E. What is the measure of arc ?

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Answer:

Step-by-step explanation:

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3 years ago

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9. Your bank account has a balance of $145.67. You make a withdrawal

Nataliya [291]

There is $103.15 in your bank account.

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3 years ago

Which fraction has a terminating decimal as its decimal expansion?

alex41 [277]

'One third' as a decimal is 1 ÷ 3 = 0.333333..... ⇒ The decimal is recurring

'One fifth' as decimal is 1 ÷ 5 = 0.2 ⇒ The decimal terminates at the tenth value

'One seventh' as decimal 1 ÷ 7 = 0.142857142857.... ⇒ The decimal is recurring for every digit between 1 and 7

'One ninth' as decimal 1 ÷ 9 = 0.111111.... ⇒ The decimal is recurring

Answer: one fifth

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4 years ago

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Solve the system algebraically. Check your work.

Luden [163]

answer.

Answer:

x=2 and y=0 is the required result.

Step-by-step explanation:

We have been given system of equations:

5x+2y=105x+2y=10 (1)

And 3x+2y=63x+2y=6 (2)

We will use elimination method:

Multiply 1st equation by 3 and 2nd equation by 5 we get:

15x+6y=3015x+6y=30 (3)

15x+10y=3015x+10y=30 (4)

Now subtract (4) from (3) we get:

-4y=0−4y=0

y=0y=0

Now, put y=0 in (1) equation:

5x+2(0)=105x+2(0)=10

5x=105x=10

x=2x=2

Hence, x=2 and y=0

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4 years ago