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ElenaW [278]
3 years ago
6

The custom shade or purple paint is made by mixing 5 parts blue paint with 3 parts red paint. The employees in the paint departm

ent of a home improvement store use this table to determine the amounts of blue and red paint needed to create this color for their customers. How much red paint is needed to make 28 pints of the custom shade of purple paint?
PLEASE HELP ME !
Mathematics
1 answer:
dem82 [27]3 years ago
7 0
Since we use 5 parts blue and 3 parts red, the total sections is 8.

28/8 = 3.5

We want to find the red which is 3 parts.

3.5 * 3 = 10.5.

Your answer should be 10.5 pints of red. Hope this helps!
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How do you rewrite the equation in the form 52m = 460
max2010maxim [7]
The answer is 115/13
8 0
4 years ago
the name Joe is very common at a school in one out of every ten students go by the name. If there are 15 students in one class,
kumpel [21]

Using the binomial distribution, it is found that there is a 0.7941 = 79.41% probability that at least one of them is named Joe.

For each student, there are only two possible outcomes, either they are named Joe, or they are not. The probability of a student being named Joe is independent of any other student, hence, the <em>binomial distribution</em> is used to solve this question.

<h3>Binomial probability distribution </h3>

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • One in ten students are named Joe, hence p = \frac{1}{10} = 0.1.
  • There are 15 students in the class, hence n = 15.

The probability that at least one of them is named Joe is:

P(X \geq 1) = 1 - P(X = 0)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{15,0}.(0.1)^{0}.(0.9)^{15} = 0.2059

Then:

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.2059 = 0.7941

0.7941 = 79.41% probability that at least one of them is named Joe.

To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377

8 0
3 years ago
The equation y= -5.131x^2 + 31.821x - 3.333 approximates the number of people standing in line to catch a commuter train x hours
GREYUIT [131]
The answer should be D since after 5 am to 7 am only two hours have passed so x=2, and then you plug in the x as 2 and solve it. You might get not around answer like 39.785 but when you round it, it would be 40.
4 0
3 years ago
Read 2 more answers
Can someone help me with these math problems please? I need it done by tonight if someone can please help me by then...I'll make
kotegsom [21]

Answer:

For question 3, you would just add 2 to the x values and subtract 2 from the y values, so it would be:

J' (-2, 5)

K' (2, 6)

L' (1, 2)

M' (-3, 1)

For question 4 you would subtract 7 from the x values and 6 from the y values, and that would be:

W' (-6, 1)

X' (-1, -1)

Y' (-3, -6)

Z' (-8, -4)

For question 9 you would end up with:

X' (6, -5)

Y' (7, 1)

Z' (4, 0)

For question 10 you would end up with:

Q' (-1, 2)

R' (1, 7)

S' (-2, 6)

T' (-4, 1)

For question 11 you would end up with:

L' (4, 1)

M' (8, 5)

N' (6, 7)

P' (2, 3)

For question 12 you would end up with:

G' (6, -7)

H' (6, -4)

I' (1, -7)

Hope this is what you were looking for!

 

Step-by-step explanation:


4 0
3 years ago
A scientist is studying bacteria and records the number of bacteria over time. The scientists determines that the function N(t)=
Cloud [144]

Answer:

(A) The number of bacteria is originally 300 and increases by 30% every hour

Step-by-step explanation:

I am assuming the function should actually read:

N(t)=300\cdot 1.30^t

(i.e., there should be a "t" in the exponent. if this is not the case please disregard my answer).

According to the above exponential function, the initial amount 300 grows as (1+0.3)*300=300+0.3*300. In other words it increases by 30% every hour (t).

Your answer choice (A) is likely a candidate, except I am missing "every hour" at the end (again, am assuming this was omitted by mistake)


6 0
4 years ago
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