Answer:
57, 53, 49, 45
Step-by-step explanation:
Substitute for the n for n=1,2,3,4 so the first term is 57-4(1-1) so =57-4(0) so
a(1) = 57-0 = 57 so that is the 1st term
2nd term 57-4(2-1) so =57-4(1) so a(2) = 57-4 = 53, etc.
Answer:
The number of once is 9.1
The number of hundreds is 8.9
Step-by-step explanation:
Given as :
The total of digits having ones and hundreds = 900
The sum of digits = 18
Let The number of ones digit = O
And The number of hundreds digit = H
So, According to question
H + O = 18 .........1
100 × H + 1 × O = 900 ........2
Solving the equation
( 100 × H - H ) + ( O - O ) = 900 - 18
Or, 99 H + 0 = 882
Or , 99 H = 882
∴ H = 
I.e H = 8.9
Put the value of H in eq 1
So, O = 18 - H
I.e O = 18 - 8.9
∴ O = 9.1
So, number of once = 9.1
number of hundreds = 8.9
Hence The number of once is 9.1 and The number of hundreds is 8.9
Answer
The answer to your question is A.
Answer:
in the pics
Step-by-step explanation:
In case you are wondering, I used the pythagorean theorem. If you want to learn how to use it I suggest you google it, there are plenty of sites that explain how to use it.
If you have any questions about the way I solved it, don't hesitate to ask me in the comments below :)