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3 years ago

Triangle XYZ is a right triangle with the right angle at vertex Y.

Mathematics

2 answers:

asambeis [7]3 years ago

5 0

Answers:
Angle X must be 45 degrees.
Angle Z must be 45 degrees.
The sum of angles X and Z must be equal to 90 degrees.

nasty-shy [4]3 years ago

5 0

Acute
Acute
Equal to
I checked

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What is the length of a base of a right triangle with an area of 15 meters and a height of 3 meters?

Nina [5.8K]

Answer:

Step-by-step explanation:

15 = 1/2 * b * 3

15 * 2 = 3 * b

b = 30/3

b = 10 m

5 0

2 years ago

A line passes through the point (–2, 7) and has a slope of –5.

ICE Princess25 [194]

Answer:

Step-by-step explanation:

Let's create an equation in point-slope form, which is: $y-y_1=m(x-x_1)$ , where $(x_1,y_1)$ is the point and m is the slope.

Here, our point is (-2, 7) and our slope is m = -5 so plug these in:

$y -7=-5*(x-(-2))$

$y -7=-5*(x+2)$

Now, if (a, 2) lies on this line, then it should satisfy the equation. So plug in a for x and 2 for y:

2 - 7 = -5(a + 2)

-5 = -5(a + 2)

Divide by -5:

1 = a + 2

Subtract 2 from both sides:

a = -1

Thus, the answer is B.

Hope this helps!

5 0

3 years ago

Read 2 more answers

PLEASSEEEEEE HELPPPPPP! WILL GIVE BRAINLIEST.

4vir4ik [10]

First replace x and y by 3 and 4.

(3*(x)+1)/(4*(y)^2)

((3*(3))+1)/(4*((4)^2)) = (9+1)/(4*16) = 10/64 = 5/32.

5/32 is your answer.

Please mark me as brainliest!

3 0

2 years ago

Please help me.... I didn't understand the question

ira [324]

19 squares are or shaded so it’s 19%

7 0

2 years ago

Read 2 more answers

Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega

AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

To find the simplified form of the given expression :

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

$=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2$ ( using the property $(ab)^m=a^m.b^m$ )

$=(2^6)(3^{-12})\times (2^{-6})(3^4)$ ( using the property $(a^m)^n=a^{mn}$

$=(2^6)(2^{-6})(3^{-12})(3^4)$ ( combining the like powers )

$=2^{6-6}3^{-12+4}$ ( using the property $a^m.a^n=a^{m+n}$ )

$=2^03^{-8}$

$=\frac{1}{3^8}$ ( using the property $a^{-m}=\frac{1}{a^m}$ )

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

6 0

3 years ago

Read 2 more answers