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3 years ago

If there are 736 students in a school, prove that at least three students have a birthday on the same day of the year.

Mathematics

1 answer:

serg [7]3 years ago

4 0

Step-by-step explanation:

736 / 365 = 2R6

So even if the first 365 students all have different birthdays, and the next 365 students also all have different birthdays, then there are 2 students for every birthday. The last 6 students therefore share a birthday with at least 2 other students. So there are at least 3 students who share a birthday.

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The next two term is 13 and 16 respectively.

Step-by-step explanation:

here,

a1 = -2

a2 = 1

a3 = 4

a4 = 7

a5 = 10

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a6 = a5 + d

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