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Mamont248 [21]
3 years ago
14

If a scientist mixed 20% saline solution with 70% saline solution to get 10 gallons of 30% saline solution, how many gallons of

20% and 70% solutions were mixed?
Mathematics
1 answer:
Nana76 [90]3 years ago
4 0
60% yes 12344748498383
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Find the slope of the line that passes through (-34, 72) and (31, 27).
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The answer i got is -9/13
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Brandon makes lemon water by adding of a cup of sliced lemon to 2 cups of water. At this rate, how many cups of sliced lemon wou
tatuchka [14]
1 lemon to 2 waters will be proportional to what he Brandon needs so:

1 lemon / 2 water = x lemon / 12 water

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He needs 6 cups of lemons
5 0
4 years ago
Write 337,060 in expanded form using exponents
Agata [3.3K]

1. expand using place value.

337,060 = 300,000 + 30,000 + 7,000 + 000 + 60 + 0


Next, we will use exponents:

300,000 = 3 * 10^5

30,000 = 3 * 10^4

7,000 = 7 * 10^3

000 = 0 * 10^2

60 = 6 * 10

0 = 0 * 10^0


then after combing these exponents, we can write the number as:

337,060 = 3 * 10^5 + 3 * 10^4 + 7 * 10^3 + 0 * 10^2 + 6 * 10 + 0 * 10^0


Finally, removing the meaningless zeroes, we would end up with:

337,060 = 3 * 10^5 + 3 * 10^4 + 7 * 10^3 + 6 * 10


3 0
3 years ago
A N S W E R Q U I C K P L E A S E
chubhunter [2.5K]

Answer:

1. A

2. D

3. D

Step-by-step explanation:

The standard form of a parabola is

y=\frac{1}{4p}(x-h)^2+k            ..... (1)

Where, (h,k) is vertex, (h,k+p) is focus and y=k-p is directrix.

1. The directrix of a parabola is y=−8 . The focus of the parabola is (−2,−6) .

k-p=-8                   ...(a)

(h,k+p)=(-2,-6)

k+p=-6            .... (b)

h=-2

On solving (a) and (b),  we get k=-7 and p=1.

Put h=-2, k=-7 and p=1 in equation (1).

y=\frac{1}{4(1)}(x-(-2))^2+(-7)

y=\frac{1}{4}(x+2)^2-7

Therefore option A is correct.

2 The directrix of a parabola is the line y=5 . The focus of the parabola is (2,1) .

k-p=5                   ...(c)

(h,k+p)=(2,1)

k+p=1            .... (d)

h=2

On solving (c) and (d),  we get k=3 and p=-2.

Put h=2, k=3 and p=-2 in equation (1).

y=\frac{1}{4(-2)}(x-(2))^2+(3)

y=-\frac{1}{8}(x-2)^2+3

Therefore option D is correct.

3. The focus of a parabola is (0,−2) . The directrix of the parabola is the line y=−3 .

k-p=-3                   ...(e)

(h,k+p)=(0,-2)

k+p=-2            .... (f)

h=0

On solving (e) and (f),  we get k=-2.5 and p=0.5.

Put h=0, k=-2.5 and p=0.5 in equation (1).

y=\frac{1}{4(0.5)}(x-(0))^2+(-2.5)

y=\frac{1}{2}(x)^2-2.5

y=\frac{1}{2}(x)^2-\frac{5}{2}

Therefore option D is correct.

5 0
3 years ago
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