this is the best thing i could find for you, good luck with your question,
5x is greater than or equal to -25
The product of 5 and a number is at least –25
we convert the given statement into inequality
product means multiplication
Let x be the unknown number
product of 5 and a number is 5x
5x is at least -25
For word at most we use <=
for word at least we use >=
So the expression becomes 5x <= -25
I am not sure, but this is what I got:
<span>Pipe ALONE = 18 hours
Pipe ALONE in 1 hour = 1/18 of the pool
Hose ALONE in 1 hour = 1/25 of the pool
TOGETHER in 1 HOUR = 1/18 +1/25 = 43/450
TOGETHER they will fill the pool in 450/43 hours
So 5/6 of the pool will take 5/6 X 450/43 = 2250/ 258 = 8.7209302 hours OR
8 hours AND 43.26 minutes ANSWER
</span>
Hope this helps!
Answers:
- Exactly 25%
- median = 450
- Not enough info (see below)
- IQR = 24
- IQR = 192
=========================================================
Explanations:
- By definition, the quartiles split the data into four equal parts. The first quartile (Q1) will have 25% of the data below it.
- The second quartile is the exact same value as the median. This is because the median splits the data into two equal halves, i.e. is at the midpoint.
- There's not enough info. We can determine that 25% of the company makes more than $60,000, but we don't know how many people total work at the company. This info is missing.
- Subtract the third and first quartiles (Q3 and Q1) to get the interquartile range (IQR). So IQR = Q3 - Q1 = 45-21 = 24
- Same idea as the previous problem. IQR = Q3 - Q1 = 316.5 - 124.5 = 192
Answer:
rate of the plane in still air is 33 miles per hour and the rate of the wind is 11 miles per hour
Step-by-step explanation:
We will make a table of the trip there and back using the formula distance = rate x time
d = r x t
there
back
The distance there and back is 264 miles, so we can split that in half and put each half under d:
d = r x t
there 132
back 132
It tells us that the trip there is with the wind and the trip back is against the wind:
d = r x t
there 132 = (r + w)
back 132 = (r - w)
Finally, the trip there took 3 hours and the trip back took 6:
d = r * t
there 132 = (r + w) * 3
back 132 = (r - w) * 6
There's the table. Using the distance formula we have 2 equations that result from that info:
132 = 3(r + w) and 132 = 6(r - w)
We are looking to solve for both r and w. We have 2 equations with 2 unknowns, so we will solve the first equation for r, sub that value for r into the second equation to solve for w:
132 = 3r + 3w and
132 - 3w = 3r so
44 - w = r. Subbing that into the second equation:
132 = 6(44 - w) - 6w and
132 = 264 - 6w - 6w and
-132 = -12w so
w = 11
Subbing w in to solve for r:
132 = 3r + 3(11) and
132 = 3r + 33 so
99 = 3r and
r = 33
