Answer:
42 units²
Step-by-step explanation:
The figure is composed of a rectangle ( middle section) and 2 triangles with the same length base and height
Area of rectangle = 7 × 4 = 28 units²
Area of 2 triangles = 2 × 
× 7 × 2 = 14 units²
Area of figure = 28 + 14 = 42 units²
The maximum weight that could be held would be 32 pounds. or six five pound weights taking up 18 inches of space, and weighing 30 Lbs, and two one pound weights adding another two inches. You could achieve a greater weight if you had a weight of one-half inch, in which case you could take six 5 lb weights and 1 two pound weight, then you could add a half inch weight bringing the weight to over 32 inches. Since we don't have a half inch weight we can't raise the weight above 32lbs.
Answer:
Yes, the triangles are congruent by ASA
Step-by-step explanation:
we know that
If any two angles and the included side are the same in both triangles, then the triangles are congruent by Angle-Side-Angle (ASA)
In this problem
LK=MJ
∠KLJ=∠KMJ
∠LKJ=∠MJK
so
Two angles and the included side is equal in triangle JKL and triangle KJM
therefore
JKL≅KJM ----> by ASA
Answer: oof thats a hard one ummmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm
Step-by-step explanation:
Area = length x width
264 = length x 11
/11 /11
24 = length
ANSWER: 24 yards = length
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