Answer:
29 is answer.
Step-by-step explanation:
Given that the function s(t) represents the position of an object at time t moving along a line. Suppose s(2)=150 and s(5)=237.
To find average velocity of the object over the interval of time [1,3]
We know that derivative of s is velocity and antiderivative of velocity is position vector .
Since moving along a line equation of s is
use two point formula
gives the position at time t.
Average velocity in interval (1,3)
=![\frac{1}{3-1} (s(3)-s(1))\\=\frac{1}{2} [87+58-29-58]\\=29](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3-1%7D%20%28s%283%29-s%281%29%29%5C%5C%3D%5Cfrac%7B1%7D%7B2%7D%20%5B87%2B58-29-58%5D%5C%5C%3D29)
Answer:
scsdabanrdfffffatrhtrtnrghnjmgk,hghngfvs
Answer:
B. Graph of a one-to-one function.
Step-by-step explanation:
A one-to-one function will have a unique value, y, for each different value of x. The graph displayed will have values very, very close to each other as x approaches ±4, but they won't be the same even at higher values of x.
It is 348000 because if its 5 or above it rounds up and 4 or below rounds down so the 5 rounds the 7 to an 8
Answer:
Jake
Step-by-step explanation: 176 Divided by 4 divided bye divided = 44, so Jake ran only 44 minutes therefore Sarah ran more.
