Split up [1, 3] into 4 subintervals:
[1, 3/2], [3/2, 2], [2, 5/2], [5/2, 3]
each with length (3 - 1)/2 = 1/2.
The right endpoints 
are {3/2, 2, 5/2, 3}, which we can index by the sequence
with 
.
Evaluating the function at the right endpoints gives the sampling points 
, {27/4, 5, 11/4, 0}.
Then the area is approximated by
Answer:
a) 
b) (a,b) (c, d) As long as (a,b) and (c,d) are the endpoints of of the diameter.
Step-by-step explanation:
a)
1) The reduced formula of the Circumference is given by:
2) Let's expand the factored one into one closer to the pattern above:
3) Completing the square for both trinomials:
4) In the Reduced Formula, ,
b) Using the previous example to show this:
When we factor this way
We are indeed, naming "a" and "b", the coordinates of (a, b) of the first endpoint and "b" and "d" the second endpoint as well.Id est, D (2, 5) and B (6,-11).
The radius, is 
So yes, the equation of the circle can be written as
As long as (a,b) and (c,d) are the endpoints of of the diameter.
Answer:
383 children and 361 adults
Step-by-step explanation:
Let's say there are a adults and c children. Since the total number of people was 744, we can write:
a + c = 744
We also know that children's prices are $1.75 per child and adults' prices are $2 per adult. Since the total is $1392.25, we can write:
1.75c + 2a = 1392.25
Now we have a system of linear equations:
a + c = 744
1.75c + 2a = 1392.25
Multiply the first equation by 2:
2 * (a + c = 744) ⇒ 2a + 2c = 1488
Now subtract the second equation from this one:
2a + 2c = 1488
- 2a + 1.75c = 1392.25
___________________
0a + 0.25c = 95.75
c = 383
Plug this in to find a:
a + c = 744
a + 383 = 744
a = 361
There were 383 children and 361 adults.
The HA Theorem is a special case of proving that two triangles are congruent.
It states that if both hypotenuses and a pair of acute angles of two right triangles are congruent, then the triangles are congruent.
Answer:
A.32
Step-by-step explanation:
