8-2(6-4:2)
8-2(6-2)
8-2*4
8-8=0
Answer:
The answer is "
".
Step-by-step explanation:
Although the five first players are red, the very first five cards are not spaded as the spad is a black card.
Its chance of the final card mostly on deck being the ace of spades is therefore determined as:

Thus,
here is the necessary chance.
Answer:
37
Step-by-step explanation:
Answer:If a die is rolled once, determine the probability of rolling a 4: Rolling a 4 is an event with 1 favorable outcome (a roll of 4) and the total number of possible outcomes is 6 (a roll of 1, 2, 3, 4, 5, or 6). Thus, the probability of rolling a 4 is 1/6.
If a die is rolled once, determine the probability of rolling at least a 4: Rolling at least 4 is an event with 3 favorable outcomes (a roll of 4, 5, or 6) and the total number of possible outcomes is again 6. Thus, the probability of rolling at least a 4 is 3/6 = 1/2
Step-by-step explanation:For example, when a die is rolled, the possible outcomes are 1, 2, 3, 4, 5, and 6. In mathematical language, an event is a set of outcomes, which describe what outcomes correspond to the "event" happening. For instance, "rolling an even number" is an event that corresponds to the set of outcomes {2, 4, 6}. The probability of an event, like rolling an even number, is the number of outcomes that constitute the event divided by the total number of possible outcomes. We call the outcomes in an event its "favorable outcomes".
What you have to do is subtract 3 2/15 from 7 5/9. You can also use decimals but that doesn't work all the time since the are infinite numbers (you will see what I mean later on) So what you can do is find the improper fraction of each one, and subtract it from each other. It would be 68/9 - 47/15, which would give you a total of 4 19/45. YOU'RE WELCOME :)