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Arturiano [62]
4 years ago
15

PLZ HELP, WORTH 20 PTS.

Mathematics
1 answer:
victus00 [196]4 years ago
4 0

The approximate value for t is 5.54

Answer: Option B

<u>Step-by-step explanation:</u>

The law of cosines generalizes the Pythagorean formula to all triangles. It says that c^{2}, the square of one side of the triangle, is equal to a^{2}+b^{2} product times the cosine of the opposite angle. When the angle C is right, it becomes the Pythagorean formula.

                      c^{2}=a^{2}+b^{2}-2 a b \cos C

According to the given triangle in figure, the values are

a = 5

b = 4

c = t

\cos C=\cos 75^{\circ}=0.2588

Substituting all the given values in the formula, we get

          t^{2}=5^{2}+4-(2 \times 5 \times 4 \times 0.2588)

          t^{2}=25+16-10.3527

          t^{2}=41-10.3527=30.647

Taking square roots, we get the value for ‘t’ as below,

                             t=\sqrt{30.647}

                             t = 5.536 (approximately 5.54)

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Answer:

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Step-by-step explanation:

The given function is

P(x)=x^4-4x^3-5x^2+38x-30

We can find a zero of the given function by hit and trial method.

Substitute x=1 in the given function.

P(1)=(1)^4-4(1)^3-5(1)^2+38(1)-30

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The value of function is 0 at x=1 it means (x-1) is a factor of given function.

Substitute x=-3 in the given function.

P(-3)=(-3)^4-4(-3)^3-5(-3)^2+38(-3)-30

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The value of function is 0 at x=-3 it means (x+3) is a factor of given function.

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Divide the given function by x^2 + 2 x - 3, to get remaining factors.

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P(x)=(x - 1) (x + 3) (x^2 - 6 x + 10)

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x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Using quadratic formula find the zeroes of x^2 - 6 x + 10.

x=\frac{-(-6)\pm \sqrt{(-6)^2-4(1)(10)}}{2(1)}

x=\frac{6\pm \sqrt{-4}}{2}

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Answer:

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p_v =2*P(Z>2.898)=0.0038    

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 94 at 5% of signficance.  

Step-by-step explanation:

Data given and notation    

\bar X=95 represent the sample mean    

\sigma=5 represent the population standard deviation    

n=210 sample size    

\mu_o =94 represent the value that we want to test    

\alpha=0.05 represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

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We need to conduct a hypothesis in order to check if the mean is different from 94, the system of hypothesis are :    

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Alternative hypothesis:\mu \neq 94    

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:    

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z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic    

We can replace in formula (1) the info given like this:    

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Since is a two-sided test the p value would be:    

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