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Gemiola [76]
3 years ago
13

15 POINTS! ALGEBRA HOMEWORK PLEASE HELP ASAP!

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
5 0
Simplify the following:
x^3 - 2 x^3 + x - 3 x - 5 - 4

Grouping like terms, x^3 - 2 x^3 + x - 3 x - 5 - 4 = (-2 x^3 + x^3) + (x - 3 x) + (-5 - 4):
(-2 x^3 + x^3) + (x - 3 x) + (-5 - 4)

x^3 - 2 x^3 = -x^3:
-x^3 + (x - 3 x) + (-5 - 4)

x - 3 x = -2 x:
-x^3 + -2 x + (-5 - 4)

-5 - 4 = -9:
-x^3 - 2 x + -9

Factor -1 out of -x^3 - 2 x - 9:

Answer: -(x^3 + 2 x + 9)

___________________________________________________________

Yes = (-2x^3 + x - 5)+( x^3 - 3x - 4) = ( x^3 - 3x - 4)+(-2x^3 + x - 5) = True

Proof:
 Left side

Simplify the following:
x^3 - 2 x^3 + x - 3 x - 5 - 4

Grouping like terms, x^3 - 2 x^3 + x - 3 x - 5 - 4 = (-2 x^3 + x^3) + (x - 3 x) + (-5 - 4):
(-2 x^3 + x^3) + (x - 3 x) + (-5 - 4)

x^3 - 2 x^3 = -x^3:
-x^3 + (x - 3 x) + (-5 - 4)

x - 3 x = -2 x:
-x^3 + -2 x + (-5 - 4)

-5 - 4 = -9:
-x^3 - 2 x + -9

Factor -1 out of -x^3 - 2 x - 9:
<span>Answer: -(x^3 + 2 x + 9)
___________________________________________________________
Right Side.

Simplify the following:
x^3 - 2 x^3 + x - 3 x - 5 - 4

Grouping like terms, x^3 - 2 x^3 + x - 3 x - 5 - 4 = (x^3 - 2 x^3) + (-3 x + x) + (-4 - 5):
(x^3 - 2 x^3) + (-3 x + x) + (-4 - 5)

x^3 - 2 x^3 = -x^3:
-x^3 + (-3 x + x) + (-4 - 5)

x - 3 x = -2 x:
-x^3 + -2 x + (-4 - 5)

-4 - 5 = -9:
-x^3 - 2 x + -9

Factor -1 out of -x^3 - 2 x - 9:
Answer:  -(x^3 + 2 x + 9)
</span>
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a line is perpendicular to y - 5 = -1/4(x + 8) and goes through the point (-1,2). What is the lines y-intercept?
lisabon 2012 [21]

Answer:

y = 4x + 6

Step-by-step explanation:

Turn the equation we are given into slope-intercept form.

y - 5 = -1/4(x + 8)

y - 5 = -1/4x - 2

y = -1/4x + 3

The slope of a perpendicular line is the opposite reciprocal of the original line.

-1/4 -> 4/1 -> 4

Find the new y-intercept using the point given.

y = 4x + b

2 = 4(-1) + b

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6 = b

Fill in everything we solved for.

y = 4x + 6

Best of Luck!

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3 years ago
Find the area of the following figure and write your result in the empty box.<br> ​<br> ​
Sunny_sXe [5.5K]

Answer:

Area = 406

Step-by-step explanation:

First things first: Divide the shape

Here is how I did it:

21 x 16

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3 years ago
Suppose a normal distribution has a mean of 62 and a standard deviation of 4. What is the probability that a data value is betwe
Anon25 [30]

Answer:Given a normal distribution with μ = 62 and σ = 4., calculate the 68-95-99.7 rule, or three-sigma rule, or empirical rule ranges

Calculate Range 1:

Range 1, or the 68% range, states that 68% of the normal distribution values lie within 1 standard deviation of the mean

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μ ± σ = 62 ± 4.

62 - 4. <= 68% of values <= 62 + 4.

58 <= 68% of values <= 66

Calculate Range 2:

Range 2, or the 95% range, states that 95% of the normal distribution values lie within 2 standard deviations of the mean

95% of values are within μ ± 2σ

μ ± 2σ = 62 ± 2(4.)

62 - 2 x 4. <= 95% of values <= 62 + 2 x 4.

62 - 8 <= 95% of values <= 62 + 8

54 <= 95% of values <= 70

Calculate Range 3:

Range 3, or the 99.7% range, states that 99.7% (virtually ALL) of the normal distribution values lie within 3 standard deviations of the mean

99.7% of values are within μ ± 3σ

μ ± 3σ = 62 ± 3(4.)

62 - 3 x 4. <= 99.7% of values <= 62 + 3 x 4.

62 - 12 <= 99.7% of values <= 62 + 12

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Step-by-step explanation:

4 0
3 years ago
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2 Describe the solution set of y=8
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