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3 years ago

8 scholars were sharing 6 brownies each scholar got an equal amount how much did each scholar get

Mathematics

1 answer:

Eva8 [605]3 years ago

6 0

Answer:

4/3 or 1 1/3 brownie

Step-by-step explanation:

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What is the percent decrease from 95 to 68 round to the nearest percent

Setler79 [48]

The decrease is (95-68) = 27 .

As a fraction, the decrease is 27/95 of the original amount.

To change any fraction to a decimal, do the division:

(27) divided by (95) = 0.2842...

To change any decimal to a percentage, move the

decimal point two places that ==> way:

0.2842... = 28.42... %Answer:

Step-by-step explanation:

6 0

2 years ago

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getting home from trick or treat celia and emma counted their candies. half of celias candies is equal to 2/3 of emmas candies.

blagie [28]

Candies with celias and emmas is 60 and 45 respectively.

<u>Solution:</u>

Given, Getting home from trick or treat celia and emma counted their candies. Half of celias candies is equal to 2/3 of emmas candies.

They had a total of 105 candies altogether.

We have to find how many candies did each of them have.

Let the number of candies with celias be n, then number of candies with emma will be 105 – n.

Now according to given condition.

$\begin{array}{l}{\frac{1}{2} \times \text { celias candies count }=\frac{2}{3} \times \text { emmas candies count }} \\\\ {\rightarrow \frac{1}{2} \times n=\frac{2}{3} \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 n=4(105-n)} \\\\ {\quad \rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n+4 n=420} \\\\ {\rightarrow 7 n=7 \times 60} \\\\ {\rightarrow n=60}\end{array}$

Hence, candies with celias and emmas is 60 and 45 respectively.

4 0

3 years ago

Huda opened a bank account with $30.00 and deposited $25.00 every month. After several months, she had a total of $180 in her ac

krek1111 [17]

Answer: C.) 6 months

3 0

3 years ago

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The table shows a student's proof of the quotient rule for logarithms.

nikklg [1K]

Answer:

The error is at step (3) .

The correct step (3) will be,

$\log_{b}(\frac {b^{x}}{b^{y}})$

= $\log_{b}(b^{x - y})$ [by using the laws of indices]

All other steps are correct.

Step-by-step explanation:

The error is at the step (3) , because the student has tried to prove the quotient rule of logarithms by using the property i.e., 'The quotient rule of logarithm' itself , i.e. ,by assuming the property does hold before proving it. So, the proof is fallacious.

The correct step (3) will be,

$\log_{b}(\frac {b^{x}}{b^{y}})$

= $\log_{b}(b^{x - y})$ [by using the laws of indices]

All other steps are correct.

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3 years ago

The square root of a number that is not a perfect square will need to be rounded to the nearest whole number.

mariarad [96]

Answer:

false because rounding it will not show the exact number

6 0

3 years ago

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