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3 years ago

Someone help me with this xD

Mathematics

2 answers:

gtnhenbr [62]3 years ago

8 0

Answer:
The first option:

Explanation:
The other nets would have two faces overlapping if you were to fold it

I hope this helps! Comment if you have any questions :)

weeeeeb [17]3 years ago

7 0

Answer:

the last one

Step-by-step explanation:

the bottom right

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Equivalent this problem -3(4 – 2g) – 6?

polet [3.4K]

Answer:

-12 + 6g - 6

Step-by-step explanation:

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2 years ago

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On a vacation in Puerto Rico rose jumped off a cliff into a river in El Yunque go forest reserve her height as a function of tim

gayaneshka [121]

Answer: t = 6 s

Step-by-step explanation:

When Rose hit the water, the height of the jump is 0, so: h(t) = 0.

Resolving it, we have:

-16t² + 16t + 480 = 0

To simplify the second degree equation, divided it by 16:

-t² + t + 30 = 0

Now, solve the equation using Bhaskara:

Δ = 1² - 4. (-1) . 30

Δ = 1 + 120

Δ = 121

t = $\frac{-1+\sqrt{121} }{-2}$

t₁ = $\frac{-1 + 11}{-2}$ = - 5

t₂ = $\frac{-11-11}{-2}$ = 6

Since time can be negative, it took t = 6s for Rose to hit the water.

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3 years ago

Max put 38,250 miles on his car during the three years that he owned it. At this rate, how many miles would be on his car after

saveliy_v [14]

Answer:

89,250 miles

Step-by-step explanation:

you divide 38,250 by 3 to get how many miles he drove a year, then multiply it by 7 for the seven years and you get 89,250 miles in 7 years.

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3 years ago

The total claim amount for a health insurance policy follows a distribution with density function 1 ( /1000) ( ) 1000 x fx e− =

gizmo_the_mogwai [7]

Answer:

the approximate probability that the insurance company will have claims exceeding the premiums collected is $\mathbf{P(X>1100n) = 0.158655}$

Step-by-step explanation:

The probability of the density function of the total claim amount for the health insurance policy is given as :

$f_x(x) = \dfrac{1}{1000}e^{\frac{-x}{1000}}, \ x> 0$

Thus, the expected total claim amount $\mu$ = 1000

The variance of the total claim amount $\sigma ^2 = 1000^2$

However; the premium for the policy is set at the expected total claim amount plus 100. i.e (1000+100) = 1100

To determine the approximate probability that the insurance company will have claims exceeding the premiums collected if 100 policies are sold; we have :

P(X > 1100 n )

where n = numbers of premium sold

$P (X> 1100n) = P (\dfrac{X - n \mu}{\sqrt{n \sigma ^2 }}> \dfrac{1100n - n \mu }{\sqrt{n \sigma^2}})$

$P(X>1100n) = P(Z> \dfrac{\sqrt{n}(1100-1000}{1000})$

$P(X>1100n) = P(Z> \dfrac{10*100}{1000})$

$P(X>1100n) = P(Z> 1) \\ \\ P(X>1100n) = 1-P ( Z \leq 1) \\ \\ P(X>1100n) =1- 0.841345$

$\mathbf{P(X>1100n) = 0.158655}$

Therefore: the approximate probability that the insurance company will have claims exceeding the premiums collected is $\mathbf{P(X>1100n) = 0.158655}$

4 0

2 years ago

Elizabeth is a manager at a nursery and is in charge of displaying potted trees in a row Elizabeth has 150 citrus trees and 180

vampirchik [111]

Answer: the greatest number of trees that ElizaBeth can have in a row is 30

Step-by-step explanation:

given data:

citrus trees = 150

palm trees = 180

As we have to find the greatest number of trees that Elizabeth can have in a row, we will find the GCF or greatest common factor.

150 = 2 x 3 x 5 x 5

180 = 2 x 2 x 3 x 3 x 5

Greatest common factor is = 2 x 3 x 5 = 30

Therefore, the largest number of trees that ElizaBeth can have in a row is 30.

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3 years ago