1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mafiozo [28]
4 years ago
12

Citric acid is a naturally occurring compound. what orbitals are used to form each indicated bond? be sure to answer all parts.

Chemistry
2 answers:
Tema [17]4 years ago
6 0

Answer : The orbitals that are used to form each indicated bond in citric acid is given below as per the attachment.

Answer 1) σ Bond a: C sp^{2}  O sp^{2} .

Explanation : The sigma bonds in the 'a' position involves carbon atom which undergoes sp^{2} hybridisation and has sp^{2} orbitals of carbon and as well as oxygen atoms involved in the bonding.

Answer 2) π Bond a: C has π orbitals and  O also has π  orbitals.

Explanation : The pi-bond at the 'a'position has carbon and oxygen atoms which undergoes pi-bond formation. And has pi orbitals of oxygen and carbon involved in the bonding process.

Answer 3) Bond b: O sp^{3}  H has only S orbital involved in bonding.

Explanation : The bonding at 'b' position involves oxygen and hydrogen atoms in it. It has sp^{3} hybridized orbitals and S orbital of hydrogen involved in the bonding.

Answer 4) Bond c:   C sp^{3} O sp^{3}

Explanation : The bonding involved at 'c' position has carbon and oxygen atoms involved in it. Both the atoms involves the orbitals of sp^{3} hybridized bonds.

Answer 5) Bond d:   C sp^{3}  C sp^{3}

Explanation : The bonding involved at the position of 'd' involves two carbon atoms. Therefore, they undergo sp^{3} hybridization. The orbitals involved in this hybridization are also sp^{3}.

Answer 6) Bond e:  C1 containing O sp^{2}    C2 sp^{3}

Explanation : The bonding at the 'e' position involves two carbon atoms on is containing oxygen with double bonds and the C2 carbon atom. The carbon containing oxygen has sp^{2} hybridized orbitals involved in the bonding; whereas C2 carbon ha sp^{3} orbitals.

KonstantinChe [14]4 years ago
5 0

Different orbitals are used to form each indicated bond.

Further explanation

Citric acid:

Citrus fruits (oranges, Lemon and guava, etc.) have weak organic acid which is known as citric acid. It is used as a natural preservative and also used to give acidic flavor to soft drinks and food.  

Orbitals

Atomic orbitals are regions of space around the nucleus of an atom where is the most probability of founding an electron. The atomic orbitals are involved in the formation of a covalent bond. The orbitals which are commonly filled are s, p, d and f orbitals.

Orbitals used to form bond

Following are the orbitals used to form each bond in citric acid.

  1. Ϭ Bond between a carbon and oxygen is C sp2 and O sp2 .
  2. Π Bond between carbon and oxygen is C Π and O Π .
  3. Bond between an oxygen and hydrogen of hydroxyl group O sp3 H s.
  4. Bond between carbon and oxygen of hydroxyl group C sp3 and O sp3.
  5. Bond between carbon and carbon C sp3 and C sp3.
  6. Bond between carbon and carbon of carboxyl group C1 sp2 C2 sp3.

Answer details

Subject: Chemistry

Level: College

Keywords

  • Citric acid
  • Orbitals
  • Orbitals used to form bond

Learn more to evaluate

brainly.com/question/11073849

brainly.com/question/10885719

You might be interested in
What happens to matter when it reaches absolute zero?
Gnesinka [82]
It dissolves. Hope that helped
5 0
3 years ago
WILL MARK BRAINLEISTTTT
notka56 [123]

Answer:

jkrifhcuhixjck

gvudd

Explanation:

dugucdsorfooggigj

4 0
3 years ago
Read 2 more answers
How many grams water will condense when 56,500 joules of energy is removed from steam at its boiling point
irina1246 [14]

Answer:

Start your streak by answering any question. You'll get bonus points from day 2.

5 0
3 years ago
Which of the following is not one of the three forms of soiled carbon
Tom [10]
Carbon in nature is found in three forms called allotropes: diamond, graphite, and fullerenes. Graphite, with clay, is in pencils.
4 0
3 years ago
Given that the vapor pressure of water is 17.54 Torr at 20 ∘ C, calculate the vapor‑pressure lowering, Δ P , of an aqueous solut
Ray Of Light [21]

Answer:

<u>A) The lowering in vapour pressure is 0.7839 torr</u>

<u>B) The lowering in vapour pressure is 3.1572 torr</u>

Explanation:

The relative lowering of vapour pressure formula is ::

  • Δ\frac{P}{P_{0}} = i*\frac{m*M}{1000}

where ,

  • <em>ΔP is the lowering of vapour pressure (atm/torr)</em>
  • <em>P_{0} is the vapour pressure of the solvent ([tex]atm/torr)</em>
  • <em>m is the molality of the solution ( molkg^{-1} ) </em>
  • <em>M is the molecular weight of the solvent ( g ) </em>
  • <em>i is the vant hoff factor or dissociation constan</em>

The values :

A)

  • P_{0}=17.54torr
  • m=2.50m
  • i=1
  • M(H_2O)=2+16=18g

⇒ΔP = 17.54*(1)*\frac{2.5*18}{1000}\\=0.7893torr

B)

  • P_{0}=17.54torr
  • m=2.50m
  • i=4 ( since, it's AlCl_3 it spilts into 1 Al^{3+} and 3 Cl^- ions and as a results, there are 4 ions.
  • M(H_2O)=2+16=18g

⇒ΔP = 17.54*4*\frac{2.50*18}{1000} \\=3.1572torr

7 0
3 years ago
Other questions:
  • The oxidation of NO by O3 is first order in each of the reactants, and its rate constant is 1.5 x 107 M.S1. If the concentration
    11·1 answer
  • Which of the following is true about two neutral atoms of the element gold? (1 point) The nucleus is missing in both. Each has a
    12·1 answer
  • HELP ASAP!!!!!!!!!!! * worth 35 points + brainliest *
    11·2 answers
  • A system is in equilibrium when the rate of the forward reaction is _____ the rate of the reverse reaction.
    12·2 answers
  • What is the Moles of CO2 in 2.00 L at STP? *
    12·1 answer
  • C+o2 = co2 is it combustion
    13·2 answers
  • Zinc+oxygen What is the reaction?
    7·1 answer
  • -1
    5·1 answer
  • Which phrase describes a typical feature of plains?
    8·2 answers
  • Help me plssssssssss
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!