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3 years ago

5

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1 answer:

Phantasy [73]3 years ago

7 0

Carbonation isn’t a force that causes such

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In nature, Chlorine-35 isotopes (35 amu) make up 75

dalvyx [7]

35 x 75% + 37 x 25% = 35.5

3 0

3 years ago

Explain why the freezing of water into ice causes the cracks to widen

horrorfan [7]

Answer:

The freezing of water into ice causes the cracks to widen because it occupy more space.

Explanation:

When the water change its state of liquid to solid state due to decrease in temperature, it contracts means occupy less space but when the temperature reaches to 4 degree Celsius, it starts to expand. When the temperature goes below 0 degree Celsius, it will cause more expansion and occupy more space that causes the cracks to widen.

4 0

3 years ago

What evidence from the experiment shows that conduction occurred? In your answer, be sure to include the materials involved in t

alisha [4.7K]

Answer:

uhh

Explanation:

Have no clue but I hope u get the question answered

5 0

3 years ago

Read 2 more answers

SOMEONE PLEASE HELP

Zinaida [17]

Answer:

6. 7870 kg/m³ (3 s.f.)

7. 33.4 g (3 s.f.)

8. 12600 kg/m³ (3 s.f.)

Explanation:

6. The SI unit for density is kg/m³. Thus convert the mass to Kg and volume to m³ first.

1 kg= 1000g

1m³= 1 ×10⁶ cm³

Mass of iron bar

= 64.2g

= 64.2 ÷1000 kg

= 0.0642 kg

Volume of iron bar

= 8.16 cm³

= 8.16 ÷ 10⁶

$= 8.16 \times 10^{ - 6} \: kg$

$\boxed{density = \frac{mass}{volume} }$

Density of iron bar

$= \frac{0.0642}{8.16 \times 10^{ - 6} }$

= 7870 kg/m³ (3 s.f.)

7.

$\boxed{mass = density \: \times volume}$

Mass

= 1.16 ×28.8

= 33.408 g

= 33.4 g (3 s.f.)

8. Volume of brick

= 12 cm³

$= 12 \times 10^{ - 6} \: m^{3} \\ = 1.2 \times 10^{ - 5} \: m ^{3}$

Mass of brick

= 151 g

= 151 ÷ 1000 kg

= 0.151 kg

Density of brick

= mass ÷ volume

$= \frac{0.151} {1.25 \times 10^{ - 5} } \\ = 12600 \: kg/ {m}^{3}$

(3 s.f.)

6 0

3 years ago

Write the empirical formula for at least four ionic compounds that could be formed from the following ions:

love history [14]

Answer:

$FeSO_{4},FeCH_{3}CO,Fe_{2}(SO_{4})_{3},Fe_{2}(CH_{3}CO)_{3}$

Explanation:

Empirical formula of ionic compound formed by two ions $A^{x+}$ and $B^{y-}$ is $A_{y}B_{x}$ (for $x\neq y$ ) of AB (for x = y)

The above empirical formula is in accordance with charge neutrality principle

Here each cation ( $Fe^{3+}$ and $Fe^{2+}$ ) can form two ionic compounds by combining with two given anions ( $SO_{4}^{2-}$ and $CH_{3}CO^{2-}$ ).

So the four ionic compounds are: $FeSO_{4},FeCH_{3}CO,Fe_{2}(SO_{4})_{3},Fe_{2}(CH_{3}CO)_{3}$

4 0

4 years ago