Answer:
Separation technique used to separate mud and water without heating:
<u>Sedimentation-Decantation</u>
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Explanation:
<em>1.The settling of the heavier particle at the bottom when the container is left undisturbed is called </em><u><em>sedimentation.</em></u>
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<u><em>In a mixture of Mud and water :</em></u>
In this process the heavy mud particles settle at the bottom due to their high density .
2. Decantation : It is the process of pouring out the upper clear layer of the light particles.
<u><em>In a mixture of Mud and water :</em></u>
The water is lighter and form a clear layer over the settled mud particles. Hence by decantation the clear water is poured into a clean separate container
Thus mud remain in the bottom and the mixture is separated
Acid rain slowly dissolves rocks due to chemical reactions between the acid and the minerals in the rock. Differential Weathering: Softer, less resistant rocks wear away at a faster rate than more weather resistant rocks. More exposure to acid rain results in more rapid weathering.
Answer:
<u>The difference between temperature and thermal energy is that temperature measures the average kinetic speed of molecules and thermal energy is the total kinetic energy of all particles in a given substance.</u> Convection occurs when energy is transferred while the mass of a substance moves. The temperature is measured in Celsius, Kelvin, and Fahrenheit. The temperature does not depend on the quantity of the substance – it is related to the average kinetic energy of the particles. The thermal energy depends on the quantity of the substance – it is related to the total kinetic energy of the particles.
Answer:
C. 33.6L
Explanation:
Based on the reaction, 2 moles of HCl reacts producing 1 mole of hydrogen.
To solve this question we must find the moles of hydrogen produced using the reaction. Then, with combined gas law (PV = nRT) we can find the volume produced:
<em>Moles H2:</em>
3.00 moles HCl * (1mol H2 / 2mol HCl) = 1.50 moles H2 are produced
<em>Volume:</em>
PV = nRT
V = nRT / P
<em>Where P is pressure = 1atm at STP</em>
<em>V is volume = Our incognite</em>
<em>n are moles of the gas = 1.50 moles</em>
<em>R is gas constant = 0.082atmL/molK</em>
<em>T is absolute temperature = 273.15K</em>
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V = nRT / P
V = 1.50mol*0.082atmL/molK*273.15K / 1atm
V = 33.6L
<h3>C. 33.6L</h3>
The answer to this question is 10.038
