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VARVARA [1.3K]
3 years ago
6

The rectangle shown has a perimeter of 48 cm and the given area. Its length is 6 more than twice its width. Write and solve a sy

stem of equations to find the dimensions of the rectangle.
Mathematics
1 answer:
melamori03 [73]3 years ago
4 0

Answer:

The length of the rectangle is 18 cm

The width of the rectangle is 6 cm

Step-by-step explanation:

Let

x-----> the length of the rectangle

y----> the width of the rectangle

we know that

The perimeter of the rectangle is

P=2(x+y)

we have

P=48\ cm

so

48=2(x+y) ------> equation A

x=2y+6 ------> equation B

Substitute equation B in equation A and solve for y

48=2(2y+6+y)

48=2(3y+6)

48=6y+12

6y=48-12

y=36/6=6 cm

Find the value of x

x=2(6)+6=18 cm

The area of the rectangle is

A=xy

A=18*6

A=108 cm^2

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The length of a rectangle is twice the width. Given that the perimeter of the rectangle is 24 feet, how many square feet are in
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