10 is the answer hope that's what it was
We are given:
p = probability = 0.12<span>
n = total students = 39 </span>
x = left handers = 5<span>
u = mean = p* n = 4.68
σ = standard dev = √ ( n*p*(1-p)) = √ ( 39 * 0.12 * 0.88 ) =
2.03</span>
Calculating for the z score:
z = (x – u) / σ<span>
z = (5 – 4.68) / 2.03</span>
<span>z
= 0.1576 = 0.16
</span>
Using the standard tables for z, the p value is:
p value = 0.5636 = 56.36%
Hence there is a 56.36% chance.
<span> </span>
Answer:
2nd one i think
Step-by-step explanation:
Answer:
Step-by-step explanation:
We have the equations
4x + 3y = 18 where x = the side of the square and y = the side of the triangle
For the areas:
A = x^2 + √3y/2* y/2
A = x^2 + √3y^2/4
From the first equation x = (18 - 3y)/4
So substituting in the area equation:
A = [ (18 - 3y)/4]^2 + √3y^2/4
A = (18 - 3y)^2 / 16 + √3y^2/4
Now for maximum / minimum area the derivative = 0 so we have
A' = 1/16 * 2(18 - 3y) * -3 + 1/4 * 2√3 y = 0
-3/8 (18 - 3y) + √3 y /2 = 0
-27/4 + 9y/8 + √3y /2 = 0
-54 + 9y + 4√3y = 0
y = 54 / 15.93
= 3.39 metres
So x = (18-3(3.39) / 4 = 1.96.
This is a minimum value for x.
So the total length of wire the square for minimum total area is 4 * 1.96
= 7.84 m
There is no maximum area as the equation for the total area is a quadratic with a positive leading coefficient.
I think the answer is 3/2 but i am not sure
