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3 years ago

5

Element X decays radioactively with a half life of 12 minutes. If there are 690 grams of Element X, how long, to the nearest ten

th of a minute, would it take the element to decay to 30 grams?

1 answer:

Alexeev081 [22]3 years ago

7 0

Answer:

the answer and explanation of the question is in the picture

Step-by-step explanation:

hope this helps

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Step-by-step explanation:

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Read 2 more answers

Determine g(x + a) – g(x) for the following function.<br> g(x) = 5x2 + 2x

dusya [7]

Answer:

$g(x + a) - g(x) = 10ax + 5a^2 + 2a$

Step-by-step explanation:

We are given the function:

$g(x) = 5x^2 + 2x$

And we want to determine:

$\displaystyle g(x+a) - g(x)$

Substitute:

$\displaystyle \begin{aligned}g(x + a) - g(x) &=\left[5(x+a)^2 + 2(x+a)\right] -\left[5x^2+2x\right] \end{aligned}$

And simplify:

$\displaystyle \begin{aligned}g(x + a) - g(x) &=\left[5(x+a)^2 + 2(x+a)\right] -\left[5x^2+2x\right] \\ \\ &= \left(5(x^2 + 2ax + a^2) + (2x + 2a) \right) + \left(-5x^2 - 2x\right) \\ \\ &= \left((5x^2 + 10ax + 5a^2) + (2x + 2a)\right) + \left(-5x^2 - 2x\right) \\ \\ &= (5x^2-5x^2) + (10ax + 2x - 2x) + (5a^2+2a) \\ \\ &= 10ax + 5a^2 + 2a \end{aligned}$

In conclusion:

$g(x + a) - g(x) = 10ax + 5a^2 + 2a$

3 0

3 years ago