Answer:
since M lies between point A and B , we came to know that,
M(4,6) =(x,y)
A(-2,-1)=(x1 ,y1)
B( _, _ )=(x2,y2)
Now using mid point formula,
x=x1×x2÷2 y=y1+y2÷2
so, point B is (10,13)
Answer:
Area=15
Step-by-step explanation:
Area=bh1/2
6*5=30
30*1/2
15
Answer:
Step-by-step explanation:
Recall, if we have a polynomial of the form 
, then we say that a is a zero of multiplicity k and b is a zero of multiplicty m. For example, in the polynomial of the form 
-5 is a zero of multiplicity 10 and 2 is a zero of multiplicity 3. If we want to know the degree of the polynomial, just add the multiplicity of both zeros (13 in our example).
In this case, we know that the degree of our polynomial should be at least 3(multiplicity 2 and multiplicity 1). So, lets take the polynomial of the form
.
In here, a is a zero with multiplicity 1 and b is a zero with multiplicity 2. We are also given that
.
Which implies that 
. Since the square of any number is a positive number, it must happen that a>0. So, we have that
![b= \pm \sqrt[]{\frac{1}{a}}](https://tex.z-dn.net/?f=b%3D%20%5Cpm%20%5Csqrt%5B%5D%7B%5Cfrac%7B1%7D%7Ba%7D%7D)
.
We can choose any value of a and solve for b. Let us choose a=4. So we can have b=1/2 or b=-1/2. Let's use b=1/2. So our polynomial would be
which we can easily check that f(0)=-1.
Answer:
a) Yes
b) Not a right triangle
Step-by-step explanation:
<h3><u>Part (a)</u></h3>
The sum of the lengths of any 2 sides of a triangle is greater than the length of the 3rd side.
7 + 8 = 15 > 9
7 + 9 = 16 > 8
8 + 9 = 17 > 7
Therefore, a triangle with side lengths 7, 8 and 9 <u>can</u> be made.
<h3><u>Part (b)</u></h3>
To determine if the triangle is a right triangle, use Pythagoras' Theorem:
a² + b² = c² (where a and b are the legs, and c is the hypotenuse)
The hypotenuse is the longest side, therefore:
Substituting these values into the formula:
⇒ a² + b² = c²
⇒ 7² + 8² ≠ 9²
⇒ 113 ≠ 81
As 7² + 8² ≠ 9² then the triangle is <u>not</u> a right triangle.
Thirteen percent of 15 is 1.95
