Find the area of each shape and add.Let's start with the first semi-circle(half-circle)
If the area of a circle is πr² , then the area of a semi-circle is 1/2πr² where is 22/7 or 3.14, and r is the radius which is 1.8 meters
A=1/2πr²
A=1/2*22/7*1.8*1.8
A=5.09 m²(rounded to nearest hundredth)
Since the semi-circles are two and have the same radius, multiply the area of the first one by two or go through the same process again.
So 5.09 *2=10.18meters square is the area of the two semi-circles
Now, let's find the area of a rectangle which is length times width, where length is 6 meters and width is (1.8+1.8, because 1.8 is half the width)=3.6 meters
A=l*w
A=6*3.6
A=21.6meters square
Therefore the area of the shape is 10.18m²+21.6m²=219.888m²
83.800 ÷ 1.479 = 56.65 ≈ 56.7 litres of diesel Steve buyed ;
Answer: 15.2
Step-by-step explanation:
(14)^2 + (6)^2 = c^2
196 + 36 = c^2
232 = c^2
Square root both sides
15.231546 = c
15.2 ≈ c
Answer:
Step-by-step explanation:
We are given two velocity vectors with its three components in unit notation:
Airplane's velocity:
Crosswind velocity:
Now, if we want to know the velocity of the airplane when it is affected by the wind, we have to add these two velocity vectors:
Adding both vectors:
In 
,
$a$ is the real part
$ib$ is the imaginary part.
Comparing, we get:
Real part: $91$
Imaginary part: $-27i$
