Answer:
Original claim is 
Opposite claim is 
Null and alternative hypotheses:
Significance level: 0.01
Test statistic:
We can use TI-84 calculator to find the test statistic and P-value. The steps are as follows:
Press STAT and the scroll right to TESTS
Scroll down to 2-SampTTest... and scroll to stats.
Enter below information.
Pooled: Yes
Calculate.
The output is in the attachment.
Therefore, the test statistic is:
P-value: 0.4412
Reject or fail to reject: Fail to reject
Final Conclusion: Since the p-value is greater than the significance level, we, therefore, fail to reject the null hypothesis and conclude that the there is sufficient evidence to support the claim that the samples are from populations with the same mean.
Answer:
Step-by-step explanation:
For this case we can use the formula for the future value with compound interest given by:
(1)
For this case since the interest is compounded quarterly we have 3 periods each year, since we have 3 quarters in a year.
r represent the rate =0.026
t = 6 represent the number of years
P = 3200 represent the amount invested at the begin
If we apply the formula (1) we got:
So then the balance after 6 years would be approximately 50995 with the conditions provided.
Answer: 50
Step-by-step explanation:
Answer:
Choice D
Step-by-step explanation:
You use the formula V=pi(radius^2)(h). Once you take the pi out and plug in the numbers, you should get V= 6^2(9). You get 324 with the pi added on after it.
In a calculator you would take 82 * 0.63 which equals 51.66
