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Rina8888 [55]
3 years ago
15

A rectangular prism has a surface area of 8 square feet. A similar rectangular prism has a surface area of 200 square feet. How

many times larger is the surface area of the larger prism?
5
10
25
625
Mathematics
2 answers:
natita [175]3 years ago
7 0

It would be 25 how I got that answer was I did 200 ÷ 8 and that gave me 25

Dmitry_Shevchenko [17]3 years ago
7 0

Answer:

25

Step-by-step explanation:

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Plz help me solve this
posledela

1.-28×-28×-28+13×13×13+16×16×16

=21,952+2,197+4,096

=28,245.

2.12×12×12+-7×-7×-7+-5×-5×-5

=1,728+-343+-125

=1,260

6 0
3 years ago
Rewrite! Write an new and equivalent equation that is easier to solve
Marysya12 [62]

\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

  • Given - <u>an </u><u>equation</u><u> </u><u>in </u><u>a </u><u>standard</u><u> </u><u>form</u>

  • To do - <u>simplify</u><u> </u><u>the </u><u>equation</u><u> </u><u>so </u><u>as </u><u>to </u><u>obtain </u><u>an </u><u>easier </u><u>one</u>

<u>Since </u><u>the </u><u>equation</u><u> </u><u>provided </u><u>isn't</u><u> </u><u>i</u><u>n</u><u> </u><u>it's</u><u> </u><u>general</u><u> </u><u>form </u><u>,</u><u> </u><u>let's</u><u> </u><u>first </u><u>convert </u><u>it </u><u>~</u>

<u>General</u><u> </u><u>form </u><u>of </u><u>a </u><u>Linear</u><u> equation</u><u> </u><u>-</u>

\bold{ax  + b = 0}

<u>T</u><u>he </u><u>equation</u><u> </u><u>after </u><u>getting</u><u> </u><u>converted</u><u> </u><u>will </u><u>be </u><u>as </u><u>follows</u><u> </u><u>~</u>

- 7 + ( \frac{4x + 2}{2} )  = 8 \\  \\ \implies \:  \frac{ - 14 + 4x + 2}{2}  = 8 \\  \\  \implies \:  - 14 + 4x + 2 = 16 \\  \\ \implies \: 4x = 16 + 14 - 2 \\  \\ \implies \: 4x = 28 \\  \\\bold{ General \: form \:  \dashrightarrow  \: 4x - 28 = 0}

hope helpful ~

6 0
2 years ago
What is 19.184 times 0.46
Anni [7]
19.184*0.46=8.82464 the answer is: 8.82464
6 0
3 years ago
Read 2 more answers
I need helps ASapP please help look at pictures
vampirchik [111]

Answer:

I can help you but I'm not see it clear

7 0
3 years ago
What basic trigonometric identity would you use to verify that
Dafna1 [17]

Given the equation:

\frac{\sin^2x+\text{cos}^2x}{\cos x}=\sec x

Let's determine the trigonometric identity that you could be used to verify the exquation.

Let's determine the identity:

Apply the trigonometric identity:

\sin ^2x+\cos ^2x=1

\cos x=\frac{1}{\sec x}

Replace cosx for 1/secx

Thus, we have:

\begin{gathered} \frac{\sin^2x+\cos^2x}{\frac{1}{\sec x}} \\  \\ =(\sin ^2x+\cos ^2x)(\sec x) \\ \text{Where:} \\ (\sin ^2x+\cos ^2x)=1 \\  \\ We\text{ have:} \\ (\sin ^2x+\cos ^2x)(\sec x)=1\sec x=\sec x \end{gathered}

The equation is an identity.

Therefore, the trignonometric identity you would use to verify the equation is:

\cos ^2x+\sin ^2x=1

ANSWER:

\cos ^2x+\sin ^2x=1

6 0
1 year ago
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