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3 years ago

Ignore my work,I was just seeing if I know how to work the problem.

Mathematics

1 answer:

HACTEHA [7]3 years ago

8 0

The values of x are 4, -4, and -2.

We can solve this by simply factorising the (x² - 16) bracket into a difference of two squares, to give us (x + 4)(x - 4), and then setting each bracket equal to 0.

When x + 2 = 0, x = -2

When x + 4 = 0, x = -4

When x - 4 = 0, x = 4

I hope this helps!

You might be interested in

Woody and Jen were paid $60 to paint the garage. Jim started at 8 a.M. And Woody didn't arrive until 10 a.M. The work was comple

Dennis_Churaev [7]

Answer:

$36

Step-by-step explanation:

Jim worked from 8am - 2 pm , which is 6 hours

Woody worked form 10am - 2pm, which is 4 hours

If we take the total time (4+6 = 10) and divide the amount they got, we have:

$60/10 = $6 per hour worked

Since Jim worked 6 hours, he will be paid 6 * 6 = $36

The rest, 60 - 36 = $24 would be paid to Woody (he worked less).

Jim's fair share of earning is $36

8 0

3 years ago

Which choice correctly describes this event? I will flip a coin and get heads 10 times in a row

BARSIC [14]

Answer:

B) Unlikely

Step-by-step explanation:

It is Unlikely that this will happen.

4 0

2 years ago

Read 2 more answers

ASAP!!! please help!!!!!!!!!!!!!!!!!!!!!

Semenov [28]

Answer:

1.5

Step-by-step explanation:

because if u divide 6 by 4 that will equal 1.5

5 0

2 years ago

Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution. At Meadowbrook Hospital, the mean we

Marina86 [1]

Answer:

Required Probability = 0.1283 .

Step-by-step explanation:

We are given that at Meadow brook Hospital, the mean weight of babies born to full-term pregnancies is 7 lbs with a standard deviation of 14 oz.

Firstly, standard deviation in lbs = 14 ÷ 16 = 0.875 lbs.

Also, Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution.

Let X = mean weight of the babies, so X ~ N( $\mu = 7 lbs , \sigma^{2} = 0.875^{2} lbs$ )

The standard normal z distribution is given by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, X bar = sample mean weight

n = sample size = 4

Now, probability that the average weight of the four babies will be more than 7.5 lbs = P(X bar > 7.5 lbs)

P(X bar > 7.5) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{7.5-7}{\frac{0.875}{\sqrt{4} } }$ ) = P(Z > 1.1428) = 0.1283 (using z% table)

Therefore, the probability that the average weight of the four babies will be more than 7.5 lbs is 0.1283 .

8 0

3 years ago

What is the union of the set (1, 4, 6, 8 1/2,10) and (1, 3, 11/2, 6, 10 1/2)

makkiz [27]

Answer:

$(1, 4, 6, 8, \frac{1}{2}, 10, 3, \frac{11}{2})$

Step-by-step explanation:

We need to find union of given sets $(1, 4, 6, \frac{1}{2}, 10)$ and $(1, 3, \frac{11}{2}, 10, \frac{1}{2})$

We know by definition that union of two given sets say A and B is set C with all the unique and common values given in set A and B.

∴ $(1, 4, 6, \frac{1}{2}, 10)$ ∪ $(1, 3, \frac{11}{2}, 10, \frac{1}{2})$ = $(1, 4, 6, 8, \frac{1}{2}, 10, 3, \frac{11}{2})$

4 0

3 years ago

Ignore my work,I was just seeing if I know how to work the problem.​

Ignore my work,I was just seeing if I know how to work the problem.