She will give her friend 28 apples, just mulitpy .35 by 80 and you get the answer
Answer:
6mph
Step-by-step explanation:
In this question, we are asked to calculate the speed at which Carol jogs, given that she has a particular speed when she jogs greater than when she walks.
Firstly, we should understand that she is taking the same distance, whether she jogs or walks.
Now, let’s say her jogging rate is x mph, this means that her walking rate would be (x - 4)mph. This is because her jogging rate is 4mph faster than her walking rate.
The total distance covered when jogging is thus 10/60 * x, while her total distance covered when walking would be 30/60 * (x-4)[we convert the time to hours]
We equate both since they are same distance:
x/6 = (x -4)/2
2x = 6(x - 4)
2x = 6x - 24
4x = 24
x = 6mph
Answer:
f (x)
[tex] \ frac [7] [4] \ time 2x [\tex]
then f (1/7) = 1/2
Answer:
P' = 1/3 P
reflection in the y-axis just changes the sign of all the x-values.
Since P" ≅ P', and P' is smaller than P, P" cannot be ≅ to P
It is, however, similar to P.
The answer is 48+3i. Hope this helped :)