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VLD [36.1K]
3 years ago
13

I would like to know what 0.5-0.125q=(q-1)/4 equals out to.

Mathematics
1 answer:
Scrat [10]3 years ago
8 0

Answer:

q = 2

Step-by-step explanation:

0.5-0.125q=(q-1)/4

At first, we have to multiply both the sides by 4.

4 × (0.5 - 0.125q) = q - 1

or, 2 - 0.5q = q - 1

now, we change the side by taking constant into the right side and the number into the left side.

2 + 1 = q + 0.5q

or, 3 = q (1 + 0.5)

or, 3 = 1.5 q

or, 1.5 q = 3

or, \frac{1.5q}{1.5} = (3 ÷ 1.5) [Dividing both the sides by 1.5]

or, q = 2

Therefore, q = 2

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On a coordinate plane, a curved line with a minimum value of (0, negative 9) and maximum values of (negative 2.3, 16) and (2.3,
nikitadnepr [17]

Answer:

(0, -9)

Step-by-step explanation:

On a coordinate plane, a curved line with a minimum value of (0, negative 9) and maximum values of (negative 2.3, 16) and (2.3, 16), crosses the x-axis at (negative 3, 0), (negative 1, 0), (1, 0), and (3, 0), and crosses the y-axis at (0, negative 9). Which is a y-intercept of the graphed function? (–9, 0) (–3, 0) (0, –9) (0, –3)

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3 years ago
Read 2 more answers
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4 years ago
Convert the complex number z = 4 - 10i from rectangular form to polar form.​
mrs_skeptik [129]

ANSWER

r = 2 \sqrt{29} ( \cos(292 \degree)  + \sin(292 \degree))

EXPLANATION

The polar form of a complex number ,

z = x + yi

is given by:

z = r( \cos( \theta)  + i \sin( \theta) )

where

r =  \sqrt{ {x}^{2} +  {y}^{2}  }

The given complex number is:

z = 4 - 10i

r =  \sqrt{ {4}^{2}  +  {( - 10)}^{2} }

r =  \sqrt{16  + 100}

r =  \sqrt{116}  = 2 \sqrt{29}

And

\theta=  \tan^{ - 1}(\frac{ y}{x} )

\theta=  \tan^{ - 1}(\frac{  - 10}{4} )

\theta=  292 \degree

Hence the polar form is :

r = 2 \sqrt{29} ( \cos(292 \degree)  + \sin(292 \degree))

6 0
3 years ago
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