Answer:
the solutions are (3, 7) and (-1, -1)
Step-by-step explanation:
Insert the " = " symbol between the two equations, obtaining:
y = x^2 - 2 = y = 2x + 1
Then x^2 - 2 = 2x + 1, or
x^2 - 2x - 3 = 0, and this can be factored into (x - 3)(x + 1) = 0.
Thus, the x values that satisfy this system are {-1, 3}.
Use y = 2x + 1 to find the corresponding y values:
y = 2(-1) + 1 = -1
and
y = 2(3) + 1 = 7
Then the solutions are (3, 7) and (-1, -1)
