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3 years ago

How to solve to system y=x^2-2 y=2x+1

Mathematics

1 answer:

vovikov84 [41]3 years ago

7 0

Answer:

the solutions are (3, 7) and (-1, -1)

Step-by-step explanation:

Insert the " = " symbol between the two equations, obtaining:

y = x^2 - 2 = y = 2x + 1

Then x^2 - 2 = 2x + 1, or

x^2 - 2x - 3 = 0, and this can be factored into (x - 3)(x + 1) = 0.

Thus, the x values that satisfy this system are {-1, 3}.

Use y = 2x + 1 to find the corresponding y values:

y = 2(-1) + 1 = -1

and

y = 2(3) + 1 = 7

Then the solutions are (3, 7) and (-1, -1)

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Hunter-Best [27]

Answer:

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Step-by-step explanation:

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