Answer:
35 different routes
Step-by-step explanation:
The problem of how many different routes are possible if a driver wants to make deliveries at 4 locations among 7 locations is a combination problem.
Combination problems are usually selection problems, of all or part of a set of options, without considering the order in which options are selected.
The number of combinations of n objects taken r at a time is: ⁿCᵣ
So, the number of ways the driver can make deliveries at 4 locations out of 7 locations of given by
⁷C₄ = 35 different ways.
Hence, 35 different routes are possible to make deliveries at 4 locations out of 7 locations.
Hope this Helps!!!
F(g(x)) = [(-7x-8)/(x-1) - 8} / [(-7x - 8)/(x-1) + 7] =
[(-7x - 8 - 8(x-1)) / (x-1)] / [(-7x - 8 + 7(x-1)) / (x-1)] = (-15x) / (-15) = x.
g(f(x)) = [-7*(x-8)/(x+7) - 8] / [(x-8)/(x+7) - 1] =
[(-7x + 56 -8*(x+7)) / (x+7)] / [(x - 8 - (x + 7)) / (x+7)] = (-15x) / (-15) = x.
So since f(g(x)) = g(f(x)) = x we can conclude that f and g are inverses.
The answer to your question is 57.6
Answer:
-0.5x² + 20x + 100
Step-by-step explanation:
Given:
R = 25x - 0.5x²
C = 100 + 5x
P = R - C
Where,
P = profits
R = Revenue
C = Cost
which expression represents her profit in dollars?
P = R - C
R = 25x - 0.5x²
C = 100 + 5x
= 25x - 0.5x² -(-100 + 5x )
= 25x - 0.5x² + 100 - 5x
= -0.5x² + 20x + 100
The expression which represents her profit in dollars is -0.5x² + 20x + 100
4120_7 = 4•7³ + 1•7² + 2•7¹ + 0•7⁰
4120_7 = 4•343 + 1•49 + 2•7 + 0•1
4120_7 = 1372 + 49 + 14
4120_7 = 1435
In base 12, we use the digits 0-9 as well as A for 10 and B for 11. So
A3B_12 = 10•12² + 3•12¹ + 11•12⁰
A3B_12 = 10•144 + 3•12 + 11•1
A3B_12 = 1440 + 36 + 11
A3B_12 = 1487
In base 36, we assign values between 10 and 35 to the letters A-Z, so that
WXYZ_36 = 32•36³ + 33•36² + 34•36¹ + 35•36⁰
WXYZ_36 = 32•46656 + 33•1296 + 34•36 + 35•1
WXYZ_36 = 1492992 + 42768 + 1224 + 35
WXYZ_36 = 1537019
