Y=3x-10 and 3x+2y=16
y=3x-10
subsitute 3x-10 for y in other equation
3x+2y=16
3x+2(3x-10)=16
distribute
3x+6x-20=16
9x-20=16
add 20 both sides
9x=36
divide both sides by 9
x=4
sub back
y=3x-10
y=3(4)-10
y=12-10
y=2
x=4
y=2
(4,2) is soluiton
Answer:
1.8 units.
Step-by-step explanation:
The questions which involve calculating the angles and the sides of a triangle either require the sine rule or the cosine rule. In this question, the two sides that are given are adjacent to each other and the given angle is the included angle. This means that the angle is formed by the intersection of the two lines. Therefore, cosine rule will be used to calculate the length of the largest side of the triangle. The cosine rule is:
b^2 = a^2 + c^2 - 2*a*c*cos(B).
The question specifies that a=0.5, B=120°, and c=1.5. Plugging in the values:
b^2 = 0.5^2 + 1.5^2 - 2(0.5)(1.5)*cos(120°).
Simplifying gives:
b^2 = 3.25.
Taking square root on the both sides gives b = 1.8 (rounded to the nearest tenth).
This means that the length of the third side is 1.8 units!!!
Answer:
Step-by-step explanation:
The formula for determining the area of a rectangle is expressed as
Area = 2(L + W)
Where
L represents the length of the rectangle.
W represents the width of the rectangle.
A proper rectangle has a length of 6 inches and a with of 8 inches. The area of the rectangle would be
6 × 8 = 48 inches^2
A square with a side length of 3 inches was cut of it. The formula for determining the area of a square is l^2
Therefore,
Area of square = 3^2 = 9 inches ^2
The area of the remaining paper would be
48 - 9 = 39 inches^2
