First, you need to find the derivative of this function. This is done by multiplying the exponent of the variable by the coefficient, and then reducing the exponent by 1.
f'(x)=3x^2-3
Now, set this function equal to 0 to find x-values of the relative max and min.
0=3x^2-3
0=3(x^2-1)
0=3(x+1)(x-1)
x=-1, 1
To determine which is the max and which is the min, plug in values to f'(x) that are greater than and less than each. We will use -2, 0, 2.
f'(-2)=3(-2)^2-3=3(4)-3=12-3=9
f'(0)=3(0)^2-3=3(0)-3=0-3=-3
f'(2)=3(2)^2=3(4)-3=12-3=9
We examine the sign changes to determine whether it is a max or a min. If the sign goes from + to -, then it is a maximum. If it goes from - to +, it is a minimum. Therefore, x=-1 is a relative maximum and x=1 is a relative miminum.
To determine the values of the relative max and min, plug in the x-values to f(x).
f(-1)=(-1)^3-3(-1)+1=-1+3+1=3
f(1)=(1)^3-3(1)+1=1-3+1=-1
Hope this helps!!
Answer:
<h2>D. y = 8x² + 8x + 4</h2>
Step-by-step explanation:
The equation of a linear function is in form:
We have:
All you really have to do is divide 80.0 by 16.0
80.0 divided by 16.0= 5
so 5 is your answer!
The median triangle is a line segment that connects the vertex and the midpoint of the opposite side. Therefore, in the given, we can say that RS = QS
Equating RS and QS, we will find the value of X
RS = QS
5x-11 = 2x+7
5x-2x = 7+11 ⇒ combine like terms
3x = 18 ⇒ divide both sides by 3 to get the x value
x = 6
Find the value of RS and QS, in this, we will show that two are equal
5(6)-11 = 2(6)+7
19 = 19 ⇒ correct
Therefore RQ is the sum of RS and QS or simply twice the length of either segment
RQ = 19 x 2 = 19 + 19 = 38 (D)
16 divided by 14, 1/7 times 8, and 16/14 goes under 8/7. 14/16, 1/16 times 14, 7 divided by 8 go under 7/8
