Both mean and median are measures of the center of a set of data.
Mean is normally preffered to the median except if there is an outlier that has a tendency to affect the mean.
An outlier is a data point that significantly differs from the other data points in a sample.
In the data set above, there is no outlier that will affect the mean.
Therefore, he should use the mean because there are no outliers that affect the mean.
Step-by-step explanation:
one could be that all the angles add up to 180
180-71= 109
∠DBC and ∠ABC must add up to 109 degrees
Okay so what we need to do is simplify 2/50, which is 1/25.
Now divide 25 into 1.
Which we will get 0.04
Now we need to move the decimal 2 times to the right.
It will be 4%
Or just multiply it by 100 and you will get 4%.
Answer:
Now, 3x 2+x+5⩾0
This is because b² −4ac=1−4×5×3
=−59 (roots are imaginary)
3x²+x+5=(x−3)² =x²+9−6x and x−3⩾0
2x²+7x−4=0
2x²+8x−x−4=0
2x(x+4)−1(x+4)=0
(2x−1)(x+4)=0
x= 1/2 and−4 but x≥3
∴ No solution.
lol hehehe
