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sleet_krkn [62]
3 years ago
7

PLS HELP GRADES ARE DUE PLSS

Mathematics
1 answer:
tino4ka555 [31]3 years ago
8 0
The correct answer is (2, -2)
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8 0
3 years ago
Stephen kicked a ball inside. The equation that represents the height h in feet of the ball after being kicked and elapsed amoun
kodGreya [7K]

Answer:

The maximum height of the ball is: 14.0625ft

Step-by-step explanation:

The missing information is:

h(t) = 30t - 16t^2

Required

The maximum height the ball attained

First, we calculate the time to reach the maximum height.

For a function: h(t) = at^2 + bt + c

The maximum is: t = \frac{-b}{2a}

So, the maximum of h(t) = 30t - 16t^2 is:

t = \frac{-b}{2a}

Where

a = -16; b = 30

So:

t = -\frac{30}{2*-16}

t = -\frac{30}{-32}

t = \frac{30}{32}

t = 0.9375

The maximum height is then calculated as:

h(t) = 30t - 16t^2

h(0.9375) = 30 * 0.9375- 16 * 0.9375^2

h(0.9375) = 28.125- 14.0625

h(0.9375) = 14.0625

8 0
3 years ago
1. Find the missing measure.
Ray Of Light [21]

Answer:

where is the figure and measure???

4 0
3 years ago
PLZZZ HURRYYYY ITS TIMEDDDDD
Vilka [71]

Answer:

Step-by-step explanation:

-2(-8x - 4y + 3/4) =

16x + 8y - 3/2 ....(-3/2 is the same as - 1 1/2)

errors.....

A. the first term should be positive

B. the second term should be positive

C. the last term should be - 1 1/2

8 0
3 years ago
A company that makes cartons finds that the probability of producing a carton with a puncture is 0.04, the probability that a ca
Over [174]

Answer:

a) C. No, a carton can have a puncture and a smashed corner.

b) The probability that a carton has a puncture or a smashed corner is P(X ∪ Y) = 0.104.

Step-by-step explanation:

To be mutually exclusive, the probability of the two events happening at the same time should be 0. But the probability that a carton has a puncture and has a smashed corner is 0.004 and not 0.

Then, we can conclude the events "selecting a carton with a puncture" and "selecting a carton with a smashed corner" are not mutually exclusive.

The answer is "C. No, a carton can have a puncture and a smashed corner."

We can calculate the probability that the carton has a puncture <em>or </em>has a smashed comer simply by adding the probability of each event:

P(X\cup Y)=P(X)+P(Y)=0.1+0.04=0.104

P(X ∪ Y): probability that a carton has a puncture or a smashed corner.

5 0
4 years ago
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