Answer:
We are given that According to government data, 75% of employed women have never been married.
So, Probability of success = 0.75
So, Probability of failure = 1-0.75 = 0.25
If 15 employed women are randomly selected:
a. What is the probability that exactly 2 of them have never been married?
We will use binomial
Formula : 
At x = 2



b. That at most 2 of them have never been married?
At most two means at x = 0 ,1 , 2
So, 


c. That at least 13 of them have been married?
P(x=13)+P(x=14)+P(x=15)



Answer:
1)
At Bombinoes, if he delivers 10 pizzas, he will make $81. y = 2.50x + 56
At Little Squeezers, if he delivers 10 pizzas, he will make $78. y = 3x + 48
At Pizza Tent, if he delivers 10 pizzas, he will make $79.50. y = 2.75x + 52
2)
Little Squeezers would pay him the most if he delivered 20 pizzas. They would pay him a total of $108.
Step-by-step explanation:
Answer:
that is the equation of the line, its slope is 1 and the y-intercept is 1 y = x + 1
Step-by-step explanation:
we can calculate the slope of this line passing through (4,5) and (8,9) like this:
m = (y2 - y1)/(x2 - x1)
m = (9 - 5)/(8 - 4)
m = 4/4
m = 1
so the slope is 1, and now we can use the equation of one point and the slope to write the line's equation:
y - y1 = m(x - x1)
y - 5 = 1*(x - 4)
y - 5 = x - 4
y = x + 1
that is the equation of the line, its slope is 1 and the y-intercept is 1
1/2X+4=X-4
1/2X+8=X
8=1/2X
16=X
(Pick one of the equations )
y=1/2X+4
y=(1/2)(16)+4
y=12
point: (16,12)
Answer:
i will have to draw it for you
Step-by-step explanation:
the reason why there is an X on the 5 squares is because you added then subtracted them