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alex41 [277]
3 years ago
13

Meg found one treasure at − 3 4 foot. Which of these location are higher than − 3 4 foot? Check all that apply. Negative StartFr

action 7 Over 8 EndFraction foot Negative one-fourth foot –1 foot –2 feet Negative StartFraction 5 Over 8 EndFraction foot. If You Help ME and GET it CORRECT u will give u brainiest
Mathematics
1 answer:
Neporo4naja [7]3 years ago
5 0

Answer:

\frac{-1}{4}and \frac{-5}{8} are the locations higher than \frac{-3}{4} foot

Step-by-step explanation:

We are given that Meg found one treasure at \frac{-3}{4}foot

We are supposed to find Which of these location are higher than \frac{-3}{4}foot?

i) -\frac{7}{8}

So, this location is not  higher than \frac{-3}{4}foot

ii)-\frac{1}{4}

So, -\frac{1}{4}>\frac{-3}{4}

So, this location is higher than\frac{-3}{4} foot

iii) - 1 foot

-1 < \frac{-3}{4}

So,this location is not  higher than\frac{-3}{4}foot

iv)-2 feet

So,this location is not  higher than\frac{-3}{4}foot

v)\frac{-5}{8}

So, this location is higher than \frac{-3}{4}foot

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3 years ago
Need help please and thank you
Georgia [21]

Answer:

y=5

x=20 degrees

K= 43 degrees

L=137 degrees

Step-by-step explanation:

aducent angles of parralologram add to 180 degrees

so (6x+17)+ (2x+3)=180

or 6x+17+2x+3=180

so 8x+20=180

and 8x=160

x=20 degrees

opposite sides of parralologram are equal so

6y-13= 32-3y

or 9y=45

and y=5

opposite angles are coonguent so

ang K= 2x+3

so K= 43 degrees

aducent angles of parralologram add to 180 degrees

so ang L+43=180

and L=137 degrees

<u>if you find my answer helpful please mark as brainliest </u>

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago
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In the function y=5x^2-2, what effect does the number 5 have on the graph, as compared to the graph of y=x^2?
allochka39001 [22]

General Idea:

The Rules for Transformations of Functions are given below:

If f(x) is the original function, a > 0 and c > 0; Then

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f(ax), \; a>1 \; SHRINK \; f(x) \; horizontally \; by \; a \; factor \; of \;\frac{1}{a}  .\\\\f(ax), \; 0

Applying the concept:

In the function y=5x^2-2, the effect that the number 5 have on the graph, as compared to the graph of y=x^2 is given below:

C.it stretches the graph vertically by a factor of 5

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