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Arturiano [62]
3 years ago
9

A cross country team is made up of 65% male runners. What fraction of the team is male?

Mathematics
1 answer:
Nikitich [7]3 years ago
5 0
Percentage is the same as a fraction over 100, where the number 100 represents a 'whole'.

Therefore, if 65% are male, it means if there were 100 runners in total, 65 of them would be male, so your fraction would be 65/100.

However, you can simplify this fraction as both 65 and 100 have common factors. So you keep dividing both numbers by its factors until there are no more common factors left. This will leave you with 13/20.

Therefore your final answer is 13/20.
You might be interested in
By selling a stool for rupees 67.50,a carpenter loses 10%.how much percent would he gain or lose by selling it for rupees 82.50.
valentina_108 [34]
Let the actual value of the stool be x.

So if the carpenter sells the stool x rupees he neither loses, now wins anything.

67.50 is the value x - 10% of x, that is:

67.50=x-0.1x
67.50=0.9x

x=67.50/0.9=75      (rupees) is the actual value of the stool.


Selling the stool for 82.50 rupees, the carpenter clearly would make a profit, say of y% of that actual value, that is y%*75.

So using the same method:

82.50=75+y%*75

y%*75=82.50-75=7.5

we can make the calculations, but clearly 7.5 is 10% of 75


Answer: 10% gain.


8 0
3 years ago
QR is the midsection of triangle GHJ, what is the length of QR?
Xelga [282]

Answer:

Step-by-step explanation:

QR = 27 ÷ 2 = 13.5

6 0
3 years ago
Which statement describes the inverse of m(x) = x^2 – 17x?
DochEvi [55]

Given:

The function is

m(x)=x^2-17x

To find:

The inverse of the given function.

Solution:

We have,

m(x)=x^2-17x

Substitute m(x)=y.

y=x^2-17x

Interchange x and y.

x=y^2-17y

Add square of half of coefficient of y , i.e., \left(\dfrac{-17}{2}\right)^2 on both sides,

x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2

x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2

x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2        [\because (a-b)^2=a^2-2ab+b^2]

Taking square root on both sides.

\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}

Add \dfrac{17}{2} on both sides.

\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y

Substitute y=m^{-1}(x).

m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}

We know that, negative term inside the root is not real number. So,

x+\left(\dfrac{17}{2}\right)^2\geq 0

x\geq -\left(\dfrac{17}{2}\right)^2

Therefore, the restricted domain is x\geq -\left(\dfrac{17}{2}\right)^2 and the inverse function is m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}.

Hence, option D is correct.

Note: In all the options square of \dfrac{17}{2} is missing in restricted domain.

7 0
3 years ago
What are the steps to solving this equation <br><br>7x+3= 9x-3-2x
Luba_88 [7]
Simplify:

7x+3=7x-3

Now 7x goes away and you get 3=-3, which cannot be true, so there is no solution
7 0
2 years ago
the flag pole in front of the school casts a shadow 40 feet long when the measurement of the angle of elevation to the sun is 31
san4es73 [151]

Answer:

I would say that the flag pole is about 120 feet long. Recall that this is an estimation.

Step-by-step explanation:

8 0
3 years ago
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