Answer:
About 41.5%
Step-by-step explanation:
<em>Given:</em>
<em>A bowl has 8 green grapes and 15 red grapes. Henry randomly chooses a grape, eats it, and then chooses another grape.</em>
<em>To Find:</em>
<em>What is the probability that both grapes are red?</em>
<em>Answer choices:</em>
<em>about 39.7%</em>
<em>about 41.5%</em>
<em>about 42.5%</em>
<em>about 44.5%</em>
<em>Solution:</em>
<em>Since, there are 8 green grapes and 15 red grapes, the total number of grapes is 23 .</em>
<em>As the red grapes are 15..</em>
<em>Thus,</em>
<em>The probability of choosing a red grape the first time is 15/23.</em>
<em>Because out of the total 23 grapes only 15 were red grape.</em>
<em>The probability of choosing the red grape the second time will be 14/22. Because the number of red grapes has already decreased by one and so is the total number of grapes after first choice</em>
<em>Hence, the probability of choosing or eating two red grapes will be :</em>
<em>15/23×14/22</em>
<em>=105/253</em>
<em>=0.415</em>
<em>= 41.5%</em>
<em>Therefore, the probability that both grapes are red is about 41.5%</em>
Answer:
2
Step-by-step explanation:
10a² : 5a² = 10 : 5 = 2
Answer: he purchased 16 ride tickets.
Step-by-step explanation:
Let x represent the number of ride tickets that he purchased.
Let y represent the number of game tickets that he purchased.
Levi purchased a total of 50 ride tickets and game tickets at the amusement park. It means that
x + y = 50
If ride tickets cost $.75 each and game tickets cost $.50 each and the total amount spent on the tickets is $29, it means that
0.75x + 0.5y = 29- - - - - - - - - - - -1
Substituting x = 50 - y into equation 1, it becomes
0.75(50 - y) + 0.5y = 29
37.5 - 0.75y + 0.5y = 29
- 0.75y + 0.5y = 29 - 37.5
- 0.25y = - 8.5
y = - 8.5/-0.25
y = 34
x = 50 - y = 50 - 34
x = 16
A. -5/3 and b -9/7. the formula is y2-y1 and x2-x1
Answer:
Remember that £ has a greater value compared to $ and vice versa.
