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Brrunno [24]
3 years ago
15

A geometry class is asked to find the equation of a line that is parallel to y – 3 = −(x + 1) and passes through (4, 2). Trish s

tates that the parallel line is y – 2 = –1(x – 4). Demetri states that the parallel line is y = –x + 6.
Mathematics
2 answers:
densk [106]3 years ago
4 0

Answer: the answer is both i just did it.

Step-by-step explanation:

asambeis [7]3 years ago
3 0
A paralell line has same slope

the equation of a line with slope of m and passing through point (x1,y1) is
y-y1=m(x-x1)

we are given
y-3=-1(x+1)
slope=-1
we don't need the point

we want it to pass through (4,2)
x1=4
y1=2

y-2=-1(x-4)
trish is right
solve for y

y-2=-x+4
y=-x+6

both are correct
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Given f(x)=x^3+2x+k.<br> and x+1 is a factor of f(x), then what is the value of k?
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Answer:

k = 3.

Step-by-step explanation:

By the Factor Theorem. if x+a is a factor of f(x)  then f(-a) = 0.

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4 0
3 years ago
Let f(x)=e^x and G(x)=x+6. What are the domain and range of g(f(x))?
Lena [83]

Answer:

Domain and Range of g(f(x)) are 'All real numbers' and {y | y>6 } respectively

Step-by-step explanation:

We have the functions, f(x) = eˣ and g(x) = x+6

So, their composition will be g(f(x)).

Then, g(f(x)) = g(eˣ) = eˣ+6

Thus, g(f(x)) = eˣ+6.

Since the domain and range of f(x) = eˣ are all real numbers and positive real numbers respectively.

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