The electric potential at point A in the electric field= 0.099 x 10 ⁻¹v
<u>Explanation</u>:
Given data,
charge = 5.5 x 10¹² C
k =9.00 x 10⁹
The electric potential V of a point charge can found by,
V= kQ / r
Assuming, r=5.00×10⁻² m
V= 5.5 x 10⁻¹²C x 9.00 x 10⁹ / 5.00×10⁻² m
V= 49.5 x 10⁻³/ 5.00×10⁻²
Electric potential V= 0.099 x 10⁻¹v
Answer:
Explanation:
Given
In R-L-C circuit frequency is very high
Inductive Reactance for inductor is given by 
Inductive Reactance for Capacitor is given by 
as frequency becomes too high then
will become very large and and
will be approximately zero .
In other words inductor behave as a very high resistance and Capacitor behaves as very small resistance
43.3m/s that is because the cyclist will be