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2 years ago

What has a positive charge a comb or rubber band?

Physics

2 answers:

kvv77 [185]2 years ago

5 0

Rubber band I think is right.

Gelneren [198K]2 years ago

3 0

Id say the rubber band

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According to the law of universal gravitation, gravity is the force keeping objects in the universe in their relative positions.

Nat2105 [25]

Answer true

Explanation

3 0

2 years ago

While buying a hot plate you notice the resistance of the hot

marissa [1.9K]

Answer:

Current = 5.45amps

Power = 654 watts

Explanation:

E =120V

I =?

R = 22.02 Ohms

I= E/R

I= 120/22.02

I = 5.45AmPs

P = ? P= E x R

E = 120V P= 120x5.45

I = 5.45 AmPs P= 654W

7 0

1 year ago

a shot putter releases the shot some distance above the level ground with a velocity of 12.0 m/s, 51.0 ∘above the horizontal. th

Savatey [412]

Answer:

15.7 m

Explanation:

The range (horizontal distance) of the projectile is determined only by its horizontal motion.

The horizontal motion is a motion with constant speed, which is equal to the initial horizontal velocity of the object:

$v_x = v cos \theta$

where

v = 12.0 m/s is the initial velocity

$\theta=51.0^{\circ}$ is the angle between the direction of v and the horizontal

Substituting,

$v_x = (12.0 m/s)(cos 51.0^{\circ} )=7.55 m/s$

We know that the projectile hits the ground in a time of

t = 2.08 s

so the horizontal distance covered is

$d = v_x t = (7.55 m/s)(2.08 s)=15.7 m$

8 0

3 years ago

A car accelerates uniformly from rest to a speed of 6.6 m/s in 6.5 s. Find the acceleration the car presents during this time?

Art [367]

Answer:

1.02 m/s²

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 0 m/s

Final velocity (v) = 6.6 m/s

Time (t) = 6.5 s

Acceleration (a) =.?

Acceleration can simply be defined as the change of velocity with time. Mathematically, it can be expressed as:

a = (v – u) / t

Where:

a is the acceleration.

v is the final velocity.

u is the initial velocity.

t is the time.

With the above formula, we can obtain the acceleration of the car as follow:

Initial velocity (u) = 0 m/s

Final velocity (v) = 6.6 m/s

Time (t) = 6.5 s

Acceleration (a) =.?

a = (v – u) / t

a = (6.6 – 0) / 6.5

a = 6.6 / 6.5

a = 1.02 m/s²

Therefore, the acceleration of the car is 1.02 m/s²

3 0

2 years ago

I have no idea of how to approach this problem

nataly862011 [7]

Answer:

p=1

Explanation:

Well me know that v=m/s

and that a=m/s^2

$(m/s)^{2} = (m/s^2)(x^p)\\\\(m^2/s^2)/(m/s^2)=x^p\\\\m^2s^2/ms^2=x^p\\\\(m^2/m)(s^2/s^2)=x^p\\\\m=x^p\\\\p=1$

Note: We don't take into account 2 because it's a scalar, it doesn't have units so it doesn't add anything to the equation.

4 0

3 years ago