Go to take picture and post it so I can see the choices for the question it will be more easy for us to answer
Answer:
#_photons = 30 photons / s
Explanation:
Let's start by finding the energy of a photon of light, let's use the Planck relation
E = h f
the speed of light is related to wavelength and frequency
c = λ f
we substitute
E = h c /λ
E₀ = 6.63 10⁻³⁴ 3 10⁸/500 10⁻⁹
E₀ = 3.978 10⁻¹⁹ J
now let's use a direct proportion rule. If the energy of a photon is Eo, how many fornes has an energy E = 1.2 10⁻¹⁷ J in a second
#_photons = 1 photon (E / Eo)
#_photons = 1 1.2 10⁻¹⁷ /3.978 10⁻¹⁹
#_photons = 3.0 10¹
#_photons = 30 photons / s
The moral law is to follow the 10 commandments, set forth and multiply, spread the word of god, and to obey the word of god. I really hope this works and if not I’m sorry. :’)
Answer:
30 V
Explanation:
Given that:
The uniform electric field = 50 N/C
Voltage = 80 V
distance = 1.0 m
The potential difference of the electric field = Δ V
E_d = V₁ - V₂
50 × 1 = 80V - V₂
50 - 80 V = - V₂
-30 V = - V₂
V₂ = 30 V
Answer:
E1_max = 866 V/m...................................... option D
Explanation:
We know that for linearly polarized light, relation between intensity and electric field is given by:
I_avg = (1/2)*c*e0*E_max^2
I_avg = (1/2)*3*10^8*8.854*10^-12*1000^2
I_avg = 1328.1 W/m^2
Now given that light is already polarized, So Using Malus's law, Intensity of light after passing through polarizer will be:
I1 = I_avg*(cosФ )^2
Ф = 30 deg, So
I1 = 1328.1*(cos 30 deg)^2 = 996.1 W/m^2
Now electric field corresponding to above Intensity will be:
I1 = (1/2)*c*e0*E1_max^2
E1_max = sqrt (2*I1/(c*e0))
E1_max = sqrt (2*996.1/(3*10^8*8.854*10^-12))
E1_max = 866 V/m