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olganol [36]
3 years ago
10

madison ran a total of 2 kilometers by running around the block 3 times. after running around the block 5 times how many kilomet

ers will she have run ?
Mathematics
2 answers:
aliya0001 [1]3 years ago
8 0
I think it is 3 1/2 I’m not sure though
tamaranim1 [39]3 years ago
6 0

Step-by-step explanation:

Write a proportion.  3 laps is to 2 km as 5 laps is to x km.

3 / 2 = 5 / x

Cross multiply:

3x = 10

Divide:

x = 10/3

x = 3⅓

Madison will have run 3⅓ kilometers.

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Which one is bigger 30% or 4 /15<br>???
Nikolay [14]
I believe 30% is bigger than \frac{4}{15}.

To find the answer, you'd have to convert both the fraction and the percent into decimal form to see which one is truly bigger. Converting the percent is fairly easy. 30% would become 0.30 is decimal form. To find the fraction in decimal form, you'd have to divide the numerator by the denominator, which would be 4 ÷ 15, which makes : 2.6666666666666666666666667. 

Now you compare easily. Which one is bigger? 2.666666666666666666666667 or 0.30? 

0.30 is bigger. So 30% is bigger out of both of them.
5 0
2 years ago
Read 2 more answers
Solve for c a(b-c)=d<br> A)c=d-ab/a<br> B)c=ab+d/a<br> C)c=ab-d/a<br> D)c=ab-d/b
bogdanovich [222]
A (b-c)=d
ab-ac=d
ab-d=a.c
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5 0
3 years ago
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HELP PLEASE IM REALLY STUCK
liberstina [14]
The 15th term will be 71. Why? Well, see below for an explanation!

By subtracting all of these numbers by the term that comes prior to them, we will find that all of them result in 5. Because of this, we know that each time the term increases, 5 is being added to the numbers. Additionally, I noticed that all of the numbers in this arithmetic sequence only end in a 1 or a 6. Because of this, we can apply the same principle when adding 5 each time:

First term: 1
Second term: 6
Third term: 11
Fourth term: 16
Fifth term: 21
Sixth term: 26
Seventh term: 31
Eighth term: 36
Ninth term: 41
Tenth term: 46
Eleventh term: 51
Twelfth term: 56
Thirteenth term: 61
Fourteenth term: 66
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By adding 5 each time and keeping in mind that the digits all end in only 1 or 6, we will find that the fifteenth term results in 71. Therefore, the 15th term is 71.

Your final answer: The 15th term of this arithmetic sequence comes down to be 71. If you need extra help, let me know and I will gladly assist you.
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2 years ago
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Kay [80]
1+16
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3 years ago
Show me the steps to solve and the solution y-2&gt;1/2(x-2)
aev [14]
<span>y-2>1/2(x-2) can be expanded as follows:  y - 2 > (1/2)x - 1

Mult. all terms by 2 to remove the fractions:

2y - 4 > x - 2

Add 4 to both sides:   2y > x + 2

Div. both sides by 2:    y > (1/2)x + 1   (answer)</span>
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