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kirill [66]
2 years ago
5

Expand: f(x)= x^4- x^3+x^2+x-

Mathematics
1 answer:
emmainna [20.7K]2 years ago
6 0
F(x) = x (x^3 - x^2 + x + 1)

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Бу2 + 13y – 8 how to factorize this?​
Anettt [7]

Answer:

We have 6y² + 13y - 8. We can rewrite this as 6x² + 16x - 3x - 8. Grouping terms we get 2x(3x + 8) - (3x + 8) and since both terms have the common factor of (3x + 8) the answer is (3x + 8)(2x - 1).

7 0
3 years ago
What is the slope of the line that contains the points (-1,9) and (5,21)
geniusboy [140]
Y-y
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X-x

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3 years ago
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3 years ago
Solve x-3/6 divided by 3-x/2 Please show work
Nataly_w [17]
\cfrac{x-3}{6}: \cfrac{3-x}{2}  = -\cfrac{3-x}{6}*\cfrac{2}{3-x}  =- \cfrac{2}{6}=- \cfrac{1}{3}
4 0
3 years ago
Simplify
OlgaM077 [116]

Answer:

see below

Step-by-step explanation:

\frac{x-1}{x^2-3x+2}+ \frac{x-2}{x^2-5x+6} +\frac{x-5}{x^2-8x+15}

we need to simplify that

x^2-3x+2=(x-1)(x-2)\\\\x^2-5x+6=(x-2)(x-3)\\\\x^2-8x+15=(x-3)(x-5)

so we can continue

\frac{x-1}{(x-1)(x-2)}=\frac{1}{x-2}\\\\\frac{x-2}{(x-2)(x-3)} =\frac{1}{x-3}\\\\\frac{x-5}{(x-3)(x-5)} =\frac{1}{x-3}

and we can put all together

\frac{1}{x-2}+ \frac{1}{x-3}+ \frac{1}{x-3}\\\\\frac{1}{x-2} +\frac{2}{x-3}\\\\\frac{x-3}{(x-3)(x-2)}+ \frac{2(x-2)}{(x-2)(x-3)} \\\\\frac{x-3+2x-4}{(x-3)(x-2)}\\\\\frac{3x-7}{x^2-5x+6}

3 0
3 years ago
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