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kirill [66]
3 years ago
5

Expand: f(x)= x^4- x^3+x^2+x-

Mathematics
1 answer:
emmainna [20.7K]3 years ago
6 0
F(x) = x (x^3 - x^2 + x + 1)

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The inner circle circumference is 52 ft. the distance between the inner and the outer circle is 8ft. By how many ft is the outer
rjkz [21]

Answer:

The outer circle is 16 feet larger than the inner circle (68 - 52).

Step-by-step explanation:

Given that the inner circle circumference is 52 feet, and the distance between the inner and the outer circle is 8 feet, to determine by how many ft is the larger outer circle, the following calculation must be performed:

The radius of a circle is equal to half its diameter. Therefore, the radius of the inner circle is 26 feet. Thus, if the distance between the two circles is 8 feet, the radius of the outer circle is 34 feet (26 + 8). Therefore, the diameter of this circle is 68 feet (34 x 2).

This implies that the outer circle is 16 feet larger than the inner circle (68 - 52).

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2 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
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