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tangare [24]
3 years ago
10

Determine the solution for x^2 + 36 > 12x

Mathematics
1 answer:
Roman55 [17]3 years ago
4 0
X<6 or  x>6 hope this helps
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Factor the expression completely over the complex numbers. y^4+14y^2+49 <br> PLZ HELP ASAP
Gre4nikov [31]

there is the explenation

8 0
3 years ago
This please asap asap
Cerrena [4.2K]

Answer: y = -2x + 5

ok done. Thank to me :>

3 0
3 years ago
2×<br><img src="https://tex.z-dn.net/?f=%20%7B2x%7D%5E%7B2%7D%20%20%3D%208x%20%2B%203" id="TexFormula1" title=" {2x}^{2} = 8x +
Contact [7]

theres a few calculaters that can do that


3 0
4 years ago
A game spinner has eight equal sections: three sections numbered 1, one section numbered 2, and four sections numbered 3. The sp
baherus [9]

Answer:

The required probability is \frac{1}{8} or 0.125

Step-by-step explanation:

Consider the provided information.

The spinner is spin twice and we want the sum should be 5.

We can get 5 if first spin gives us 2 and second spin gives 3.

Or we can get 5 if first spin gives us 3 and second spin gives 2.

There are 8 section out off which Three sections numbered 1, one section numbered 2, and four sections numbered 3.

The probability of getting 2 is \frac{1}{8}

The probability of getting 3 is \frac{4}{8}

Now, the probability that the sum of the two spins will be five is:

\frac{1}{8}\times \frac{4}{8}+\frac{4}{8}\times \frac{1}{8} =\frac{4}{64}+\frac{4}{64}=\frac{1}{8}

Hence, the required probability is \frac{1}{8} or 0.125

6 0
4 years ago
QUESTION 11.1
lawyer [7]

The group paid $ 5250 at first city and $ 6250 at second city

<u>Solution:</u>

Let x = the charge in 1st city before taxes

Let y = the charge in 2nd city before taxes

The hotel charge before tax in the  second city was $1000 higher than in the first

Then the charge at the second hotel before tax will be x + 1000

y = x + 1000 ----- eqn 1

The tax in the first city was 8.5% and the  tax in the second city was 5.5%

The total hotel tax paid for the two cities was $790

<em><u>Therefore, a equation is framed as:</u></em>

8.5 % of x + 5.5 % of y = 790

\frac{8.5}{100} \times x + \frac{5.5}{100} \times y = 790

0.085x + 0.055y = 790 ------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Substitute eqn 1 in eqn 2</u></em>

0.085x + 0.055(x + 1000) = 790

0.085x + 0.055x + 55 = 790

0.14x = 790 - 55

0.14x = 735

<h3>x = 5250</h3>

<em><u>Substitute x = 5250 in eqn 1</u></em>

y = 5250 + 1000

<h3>y = 6250</h3>

Thus the group paid $ 5250 at first city and $ 6250 at second city

8 0
3 years ago
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