Star at -20 and go back by -5 on the number line
If 7 is the value F it makes the equation true!
Answer:
Step-by-step explanation:
![\sf f(x) = 9x-10\\\\Put\ x = 8\\\\f(8) = 9(8) -10\\\\f(8) = 72-10\\\\f(8) = 62\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20f%28x%29%20%3D%209x-10%5C%5C%5C%5CPut%5C%20x%20%3D%208%5C%5C%5C%5Cf%288%29%20%3D%209%288%29%20-10%5C%5C%5C%5Cf%288%29%20%3D%2072-10%5C%5C%5C%5Cf%288%29%20%3D%2062%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h2>~AnonymousHelper1807</h2>
<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
To solve this, you distribute the -y to both terms, 2 and 4y.
It will look something like this: (2*-y)+(4y*-y)
When you simplify, look for any like terms that can be combined, and if none, then leave it as it is.
Your final answer will be: -2y-4y^2
